DIecval1,46621A@23. The mean for the SATS for all high school students was 500, with a standard deviation of 100.75 students from Cerritos were tested and they produced a mean of 510.a. Who are the groups being compared/tested?What is the dependent variable?b. What are the null and research hypotheses?c. what are the numbers needed for the z statistic?--F2WSd. What is the z statistic?e. For a two tailed test at .05 significance, the critical area is +/- 1.96. What decision do wemake?e. For a two tailed test at .05 significance, the cutoff is +/- 1.96, what decision do we make?#3n80F3E$ 4aF4RD F%59F5TGMacBook Air^6CF6Y&7HKF7U*8J5DIIF8K

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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1..
i.
1)higher or lower 2)slower or faster
3. A certain breed of cat has weights which are normally distributed with a mean of 6.2 pounds, and a standard deviation of .8 pounds. What would be the z-score of a cat which weighed 7.4 pounds? 1.50 1.20 -1.50 -1.20
4. Heights of Parents. A sociologist claims that women tend to marry men who are taller than themselves? Suppose that 20 random married couples are measured. If the difference in height for each set of parents is found by subtracting the mother's height from the father's height, the mean was 4.4 inches with a standard deviation of 4.2 inches. Use a 0.01 significance level to test the claim that the mean difference is greater than 0.
27. Which is cheaper: eating out or dining in? The mean cost of a flank steak, broccoli, and rice bought at the grocery store is $13.04 (Money.msn website, November 7, 2012). A sample of 100 neighborhood restaurants showed a mean price of $12.75 and a standard deviation of $2 for a comparable restaurant meal. a. Develop appropriate hypotheses for a test to determine whether the sample data port the conclusion that the mean cost of a restaurant meal is less than fixing a com- st sup- parable meal at home. b. Using the sample from the 100 restaurants, what is the p-value? At a = .05, what is your conclusion? Repeat the preceding hypothesis test using the critical value approach. с. || d.
3. Use the following information about the heights measured in feet of a sample of 40 Ponderosa Pine trees and 40 Eastern White Pine trees. Ponderosa Pine Trees: Mean of 77.5 ft with a standard deviation of 11.55 ft Eastern White Pine Trees: Mean of 67.25 ft with a standard deviation of 10.33 ft Is it more unusual for a Ponderosa Pine tree to have a height of 71 ft or an Eastern White Pine tree to have a height of 71 ft relative to the data of each species of tree? Use z-scores to explain your solution.
A primary measure of dispersion for sample data is the sample standard deviation, s. Choose the best option to explain what the meaning of the sample standard deviation is, in general. A. The distance between one observation and the mean. B. The average distance of an observation from the middle of the distribution. C. The average distance between observations in the sample. D. The distance between the third and first quartiles.
3. Based on information from the U.S. Census Bureau, the mean travel time to work (mins), for all workers 16 years and older was 25.3 minutes. A large company with offices in several states randomly sampled 100 of its workers to ascertain their commuting times. The sample mean was 23.9 minutes, and the population standard deviation is 6.39 minutes. At the level of significance, can it be concluded that the mean commuting time is less for this particular company? H. : H :
6. A sample of 100 adult women was taken, and each was asked how many children she had. The results were as follows: Children 0 Number of 24 Women 1 20 2 35 3 13 4 7 5 1 a. Find the sample mean number of children. b. Find the sample standard deviation of the number of children. c. Find the sample median of the number of children. d. What is the first quartile of the number of children? e. What proportion of the women had more than the mean number of children? f. For what proportion of the women was the number of children more than one standard deviation greater than the mean? g. For what proportion of the women was the number of children within one standard deviation of the mean?
2. The blood cholesterol levels of men age 55 to 64 are approximately Normal, with mean 222milligrams per deciliter (mg/dl) and standard deviation 37 mg/dl. A random sample of 58individuals will be collected and the sample mean cholesterol level will be computed. a. What is the mean of the sample mean? b. What is the standard deviation of the sample mean?
A study was conducted on the average commuting distance of students at College. The study found that the first sample of thirty students has an average commute of 23.1 miles with a sample standard deviation of 12.47 miles. The commuting mileages for a second sample of 30 students are below. a) Find the mean, median and mode for the second sample of students. b) Find the range, variance and standard deviation for the second sample students. c)

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