3. The long chord of a compound curve is parallel with the 200m common tangent. The tangent distance from the PC to the PI is 376m and the tangent distance from the PC to the intersection of the common tangent and the tangent through the PC is 120m long. Compute the long chord from PC to PT.

3. The long chord of a compound curve is parallel with the 200m common tangent. The tangent distance from the PC to the PI is 376m and the tangent distance from the PC to the intersection of the common tangent and the tangent through the PC is 120m long. Compute the long chord from PC to PT.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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QUESTION 2 The tangent thru the PC has a direction due to North; and the tangent through the PT has a bearing of N 50° E. It has a radius of 200 m. Stationing of PC is 12+060. a. Compute the tangent distance of the curve. Answer: T= b. Compute the long chord of the curve. Answer: Lc = m m c. A line is drawn from the center of the curve (at the central angle) and intersects the curve at point B. This line, when extended, makes an angle of 62° with the tangent thru PC. What is the stationing of point B? Answer: Sta. B = Note: Unit has been provided after the blank space. No need to indicate units on your answer.
A compound curve is having a common tangent of 84.50 meters long. The central angles made by the common tangent for the first and second simple curve is 16 degree and 20 degree respectively. The length of the tangent of the first curve is 38.60 meters and Sta. PI is 10+180. Determine the following: a. Station of PC b. Station of PCC c. Station of PT
In a compound curve, the line connecting the P.l. at point V and the PC is an angle bisector. VA is 270 meters and BV =90 m. The stationing of A is 6+421 and that of B is 6+721. Point A is along the tangent passing through PC while point B is along the tangent passing through PT. The PC is also along AB. a. Compute the radius of the first curve b. Compute the radius of the second curve c. Determine the length of the line connecting PC and PT.
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In a compound curve, the line connecting the PI at point V and the PCC is an angle bisector. AV is 270m and BV= 90m. The stationing ofA is 6 + 421 and that of B is 6 + 721. Point A is along the tangent passing thru the PC while point B is along the tangent passing thru the PT. The PCC is along the line AB. a.Compute the radius of the first curve passing thru the PC. b.Compute the radius of the second curve passing thru the PT. c.Determine the length of the long chord from PC to PT.
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In a compound curve, the line connecting the PI at point V and the PCC is an angle bisector. AV is 270m and BV= 90m. The stationing of A is 6 + 421 and that of B is 6 + 721. Point A is along the tangent passing thru the PC while point B is along the tangent passing thru the PT. The PCC is along the line AB. a. Compute the radius of the first curve passing thru the PC.b. Compute the radius of the second curve passing thru the PT.c. Determine the length of the long chord from PC to PT.
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In a compound curve, the line connecting the Pl at point V and the PCC is an angle bisector, AV is 250 m and BV = 90 m. The stationing of A is 6 + 420 and that of B is 6 + 720. Point A is along the tangent passing thru the PC while point B is along the tangent passing thru the PT. The PCC is along line AB. a) Compute the radius of the first curve passing thru the PC. b) Determine the length of the long chord from PC to PT.
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