In a compound curve, the line connecting the PI at point V and the PCC is an angle bisector. AV is 270m and BV= 90m. The stationing of A is 6 + 421 and that of B is 6 + 721. Point A is along the tangent passing thru the PC while point B is along the tangent passing thru the PT. The PCC is along the line AB. a. Compute the radius of the first curve passing thru the PC. b. Compute the radius of the second curve passing thru the PT. c. Determine the length of the long chord from PC to PT.
In a compound curve, the line connecting the PI at point V and the PCC is an angle bisector. AV is 270m and BV= 90m. The stationing of A is 6 + 421 and that of B is 6 + 721. Point A is along the tangent passing thru the PC while point B is along the tangent passing thru the PT. The PCC is along the line AB. a. Compute the radius of the first curve passing thru the PC. b. Compute the radius of the second curve passing thru the PT. c. Determine the length of the long chord from PC to PT.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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In a compound curve, the line connecting the PI at point V and the PCC is an angle bisector. AV is 270m and BV= 90m. The stationing of A is 6 + 421 and that of B is 6 + 721. Point A is along the tangent passing thru the PC while point B is along the tangent passing thru the PT. The PCC is along the line AB.
a. Compute the radius of the first curve passing thru the PC.
b. Compute the radius of the second curve passing thru the PT.
c. Determine the length of the long chord from PC to PT.
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