Given lines AB, BC, and CD, a reversed curve is to connect these three lines thus forming the centerline of the new road. If the degree of curvature for the first curve is 4°, compute the: a. Elements of the first curve b. Elements of the second curve c. Stationing of P.C., P.R.C., and P.T. if station of C is at 25 + 010.69m LINE DISTANCE BEARING AB 57.60 m DUE EAST N 68° E S 68° E BC 91.50 m CD 109.20 m 25+010.69m
Given lines AB, BC, and CD, a reversed curve is to connect these three lines thus forming the centerline of the new road. If the degree of curvature for the first curve is 4°, compute the: a. Elements of the first curve b. Elements of the second curve c. Stationing of P.C., P.R.C., and P.T. if station of C is at 25 + 010.69m LINE DISTANCE BEARING AB 57.60 m DUE EAST N 68° E S 68° E BC 91.50 m CD 109.20 m 25+010.69m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Given lines AB, BC, and CD, a reversed curve is to connect these three lines thus forming the centerline of the
new road. If the degree of curvature for the first curve is 4°, compute the:
a. Elements of the first curve
b. Elements of the second curve
c. Stationing of P.C., P.R.C., and P.T. if station of C is at 25+ 010.69m
LINE
DISTANCE
BEARING
AB
57.60 m
DUE EAST
ВС
91.50 m
N 68° E
CD
109.20 m
S 68° E
25 +010.69 m
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