3. The chestnut coat color of horses is due to a recessive gene, while the dominant allele results in black. The pacing gait is due to a recessive gene, whereas the dominant allele results in the trotting gait. Show the types of offspring that cou result from a cross of a black trotter (male), heterozygous for both genes, with a chestnut pacer (female). ld a. Possible genotypes for Black coat:Chestnut coat: b. Possible genotypes for Trotting gait:Pacing gairi Male possible gametes: Female possible gametes: c. Male genotype d. Female genotype: e. f. Genotypic Ratio: g. Phenotypic Ratio:

3. The chestnut coat color of horses is due to a recessive gene, while the dominant allele results in black. The pacing gait is due to a recessive gene, whereas the dominant allele results in the trotting gait. Show the types of offspring that cou result from a cross of a black trotter (male), heterozygous for both genes, with a chestnut pacer (female). ld a. Possible genotypes for Black coat:Chestnut coat: b. Possible genotypes for Trotting gait:Pacing gairi Male possible gametes: Female possible gametes: c. Male genotype d. Female genotype: e. f. Genotypic Ratio: g. Phenotypic Ratio:

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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6. A man with type B blood marries a woman with type A blood. They have the first child with bloodtype O.a. What are the genotypes of the father and the mother?b. What is the genotype and phenotype of the baby? 7. A man with type O blood marries a woman with type AB blood. What is the predicted genotypicand phenotypic ratios of their children?
4. In cocker spaniels, the following genotypes and phenotypes are found:AABB = white A-bb = red aabb = lemon AaB- = black aaB- = liver AABb = greyb. What proportion of these offspring would be expected to be black?
3. One parent is homozygous for the allele for myostatin that results in big muscles and the other parent is heterozygous (MM x Mm). a. Part A (fill in the boxes): M м M m b. Part B (fill in the boxes): Total number of offspring with the heavily muscled phenotype Proportion and percent of heavily muscled offspring Total number of offspring with the in-between phenotype Proportion and percent of in-between offspring Total number of offspring with typical muscles Proportion and percent of typical muscled offspring Total: 100%
3. Codominance is when two dominant alleles of contrastingpair fully expressed at the same time in heterozygousindividual. Which of the following situation is an example ofcodominance?A. Jo mated the red bull with the white cow to produce a roan cow.B. Melissa traces her blood type by crossing the blood type of herparents.C. James passed a genetic disorder hypertrichosis pinnae aurisor hairy ear to his son.D. Tess crosses the red carnation flower plant with white flowercarnation plant to produce a pink flower plant.
8. Albinism in humans is heritable condition resulting in the inability to produce the pigment melanin, which is responsible for hair, eye and skin coloration. The allele for the albino condition is recessive to the allele for melanin production. What is the probability of two heterozygous parents producing a family of two normal children and one albino child?
1. Use the diagram of the pedigree above, which shows inheritance of an x-linked recessive trait through a family. Select ALL of the individuals in the pedigree who must be carriers for the trait. E G B C H A
7
11. A polygenic trait is also called multiple a. continuous trait holandric gene d. X-link gene b. A plant bearing pink flowers is allowed to pollinate itself. Every generation thereafter, the plant still produces pink flowers. This condition is known as hybridization 12. C. pure breeding a. b. incomplete dominance d. segregation 13. A homozygous red-flowered plant was crossed with a homozygous white-flowered plant and resulted in an offspring with red flowers. This demonstrates a case of dihybrid cross monohybrid cross a. C. b. dominance d. pure breeding How many chromosomes does a human gamete have? 14. 12 a. C. 24 b. 23 d. 46 If a heterozygous tall plant (TI) is crossed with a short plant (t), how many percent of the offspring are heterozygous tall? 15. a. 25% с. 75% b. 50% d. 100% Critical Thinking Are you in favor of the idea that couples should undergo genetic counseling? Why? Explain why Gregor Mendel chose pea plants for his experiments. Albinism is caused by a mutation;…
1. what is the progeny difference of Sire B? 2. what is the progeny difference of Dam A?
1. Two loci found in mice are suspected to be linked. To test this hypothesis, a group of graduate students performed a test cross between mice that are true breeding for both dominant traits and mice that are true breeding for both recessive traits. Individuals from the F1 generation were crossed with individuals that express both recessive traits. The phenotypic results are shown in the table below. Use chi-square analysis to determine if the graduate students’ hypothesis is supported by the evidence. Phenotype Number of OffspringDominant 1, Recessive 2 132Dominant 1, Dominant 2 128Recessive 1, Recessive 2 118Recessive 1, Dominant 2 124 a. What are the degrees of freedom and the critical chi-square value (from the table)?b. What is the calculated chi-square value?c. Do the results support that the loci are linked or that they are independently assorted (unlinked)?
3. You are studying single gene traits in peas. These are the traits you are following: Gene Symbol Alleles enistic Pairs Appeerance of Hybrid dominant ait) Seed eoler deteric Yellow pea is dominant to green Round pea is dominant to wrinkled Purple flower is dominant to white flowers Unripe pods are dominant to ripe pods Yly R/r Yellow P/p U/u ound Wrinkied Round Flower clor You cross pollen from a pea that is of genotype YyRrPpUu with ovules from a pea whose genotype is YYrrPpUU a. How many different types of gametes can the female produce? Pod color (up) b. How many different types of gametes can the male produce? C. What fraction of the progeny will be phenotypically identical the female parent? d. What fraction of the progeny will be phenotypically identical the male parent? e. What fraction of the progeny will be homozygous at all seven loci? f. What fraction of the progeny will be heterozygous at all seven loci?
23. In horses, black color is influenced by the dominant allele B and chestnut coat color is influenced by the recessive allele b. Trotting gait is due to a dominant allele T, pacing gait to the recessive allele t. A black trotter who is homozygous for both traits is crossed to a chestnut pacer. a. What are the genotypes of the Pgeneration? b. What will be the genotype and phenotype of the F1 generation? c. Draw a punnett square showing the cross of two F1 generation horses. What is the phenotypic ratio of all the combinations?