3. Show the reaction and products formed when methyl magnesium iodide (CH3-Mg-I) is reacted with butanal (butyraldehyde), then the alcoholate formed is treated with aqueous acid. What alcohol is formed (draw its structure.)

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**3. Reaction and Product Formation with Methyl Magnesium Iodide and Butanal**

**Objective:**
To demonstrate the reaction and identify the products formed when methyl magnesium iodide (CH₃-Mg-I) reacts with butanal (butyraldehyde). The subsequent step involves treating the alcoholate formed with aqueous acid to yield an alcohol.

**Reaction Steps:**

1. **Initial Reaction:**
   - **Reagents:** Methyl magnesium iodide (CH₃-Mg-I) and butanal
   - **Process:** In the presence of butanal, the methyl group from the Grignard reagent (CH₃-Mg-I) attacks the carbonyl carbon of butanal. 

2. **Intermediate Formation:**
   - **Intermediate:** An alkoxide ion is formed as an intermediate.
   - **Structure Explanation:** The alkoxide ion structure results from the attachment of the methyl group to the carbonyl carbon, converting the carbonyl group into an alkoxide.

3. **Final Step:**
   - **Treatment:** The alkoxide is treated with aqueous acid.
   - **Product:** The final product is an alcohol, specifically 2-pentanol.
   - **Alcohol Structure:** The structure can be represented as CH₃-CH(OH)-CH₂-CH₂-CH₃, with the hydroxyl group attached to the second carbon.

This reaction is a classic example of a Grignard reagent addition to a carbonyl compound, illustrating the formation of new carbon-carbon bonds and the synthesis of alcohols.
Transcribed Image Text:**3. Reaction and Product Formation with Methyl Magnesium Iodide and Butanal** **Objective:** To demonstrate the reaction and identify the products formed when methyl magnesium iodide (CH₃-Mg-I) reacts with butanal (butyraldehyde). The subsequent step involves treating the alcoholate formed with aqueous acid to yield an alcohol. **Reaction Steps:** 1. **Initial Reaction:** - **Reagents:** Methyl magnesium iodide (CH₃-Mg-I) and butanal - **Process:** In the presence of butanal, the methyl group from the Grignard reagent (CH₃-Mg-I) attacks the carbonyl carbon of butanal. 2. **Intermediate Formation:** - **Intermediate:** An alkoxide ion is formed as an intermediate. - **Structure Explanation:** The alkoxide ion structure results from the attachment of the methyl group to the carbonyl carbon, converting the carbonyl group into an alkoxide. 3. **Final Step:** - **Treatment:** The alkoxide is treated with aqueous acid. - **Product:** The final product is an alcohol, specifically 2-pentanol. - **Alcohol Structure:** The structure can be represented as CH₃-CH(OH)-CH₂-CH₂-CH₃, with the hydroxyl group attached to the second carbon. This reaction is a classic example of a Grignard reagent addition to a carbonyl compound, illustrating the formation of new carbon-carbon bonds and the synthesis of alcohols.
Expert Solution
Step 1: Introduce the reaction

When methyl magnesium iodide is treated with butanal there occurs nucleophilic addition reaction of aldehyde.Thealdehyde.Then we get an alcoholate ,after the acidification we get 2-pentanol as the Major product.

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