3. Redraw the compound and label equivalent sets of carbons with lower-case letters. Then for each set of carbons give the & value and # of carbons it represents. letter d value # of carbons
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![Questions to be Answered
CH3
OH
ба
CH3
H3C
-OCH₂CH3
H3C CH3
H3C
Н
Н
-OCH3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6874e1f1-5298-4a44-ae8e-fa9c3662cb0d%2F1869cf48-b3dd-494d-ad88-cba45e06bd28%2Fjztixta_processed.jpeg&w=3840&q=75)
![3. Redraw the compound and label equivalent sets of carbons with lower-case
letters.
Then for each set of carbons give the value and # of carbons it represents.
letter
o value
# of carbons](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6874e1f1-5298-4a44-ae8e-fa9c3662cb0d%2F1869cf48-b3dd-494d-ad88-cba45e06bd28%2Fgk2aq17_processed.jpeg&w=3840&q=75)
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