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3. Inductor and capacitor impedances are given as: Z, = jwL and Zc 1/jwC. Assume you have a 10µF capacitor and a 10mH inductor. Calculate the impedance of these components at the following frequencies and list in the space provided: 1 MHz (1,000,000 Hz): jwL 21/jwC = Ω %D 50KHZ (50,000 Hz): jwL = 21/jwC = Ω %3D OHz: jwL 21/jwC = Ω

3. Inductor and capacitor impedances are given as: Z, = jwL and Zc 1/jwC. Assume you have a 10µF capacitor and a 10mH inductor. Calculate the impedance of these components at the following frequencies and list in the space provided: 1 MHz (1,000,000 Hz): jwL 21/jwC = Ω %D 50KHZ (50,000 Hz): jwL = 21/jwC = Ω %3D OHz: jwL 21/jwC = Ω

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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### Impedance Calculation for Inductors and Capacitors **Problem Statement:** Inductor and capacitor impedances are given by the formulas: - For inductors: \(Z_L = j\omega L\) - For capacitors: \(Z_C = 1/j\omega C\) Given: - A \(10 \, \mu F\) capacitor - A \(10 \, mH\) inductor **Task:** Calculate the impedance of these components at the following frequencies and fill in the spaces provided: 1. **Frequency: 1 MHz (1,000,000 Hz)** - Inductor impedance: \(j\omega L = \_\_\_\_\_\_\_\_\_\_\_\_) \, \Omega\) - Capacitor impedance: \(1/j\omega C = \_\_\_\_\_\_\_\_\_\_\_\_\_ \, \Omega\) 2. **Frequency: 50 KHz (50,000 Hz)** - Inductor impedance: \(j\omega L = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \, \Omega\) - Capacitor impedance: \(1/j\omega C = \_\_\_\_\_\_\_\_\_\_\_\_\_ \, \Omega\) 3. **Frequency: 0 Hz** - Inductor impedance: \(j\omega L = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \, \Omega\) - Capacitor impedance: \(1/j\omega C = \_\_\_\_\_\_\_\_\_\_\_\_\_ \, \Omega\) **Instructions:** - Use the given formulas for calculations. - \(j\) represents the imaginary unit \((j^2 = -1)\). - \(\omega = 2\pi f\) where \(f\) is the frequency in Hz. - Calculate and enter the impedance values in ohms (\(\Omega\)) for each frequency.
Transcribed Image Text:### Impedance Calculation for Inductors and Capacitors **Problem Statement:** Inductor and capacitor impedances are given by the formulas: - For inductors: \(Z_L = j\omega L\) - For capacitors: \(Z_C = 1/j\omega C\) Given: - A \(10 \, \mu F\) capacitor - A \(10 \, mH\) inductor **Task:** Calculate the impedance of these components at the following frequencies and fill in the spaces provided: 1. **Frequency: 1 MHz (1,000,000 Hz)** - Inductor impedance: \(j\omega L = \_\_\_\_\_\_\_\_\_\_\_\_) \, \Omega\) - Capacitor impedance: \(1/j\omega C = \_\_\_\_\_\_\_\_\_\_\_\_\_ \, \Omega\) 2. **Frequency: 50 KHz (50,000 Hz)** - Inductor impedance: \(j\omega L = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \, \Omega\) - Capacitor impedance: \(1/j\omega C = \_\_\_\_\_\_\_\_\_\_\_\_\_ \, \Omega\) 3. **Frequency: 0 Hz** - Inductor impedance: \(j\omega L = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \, \Omega\) - Capacitor impedance: \(1/j\omega C = \_\_\_\_\_\_\_\_\_\_\_\_\_ \, \Omega\) **Instructions:** - Use the given formulas for calculations. - \(j\) represents the imaginary unit \((j^2 = -1)\). - \(\omega = 2\pi f\) where \(f\) is the frequency in Hz. - Calculate and enter the impedance values in ohms (\(\Omega\)) for each frequency.
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