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3. In the given picture you see the motion path of cannonball. Find the maximum height it can reach, horizontal distance it covers and total time from the given information. The angle between cannonball and horizontal is 53°.

3. In the given picture you see the motion path of cannonball. Find the maximum height it can reach, horizontal distance it covers and total time from the given information. The angle between cannonball and horizontal is 53°.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please use the formulas in the second picture. 

Please write known and unknown like y = ?, x = ?, etc. too and show work in an easy to understand way.

3. In the given picture you see the motion path of cannonball. Find the maximum height it can reach, horizontal distance it covers and total time from the given information. The angle between cannonball and horizontal is 53°. V=25m/s ttotal? hmax=? h=60m X=?
Transcribed Image Text:3. In the given picture you see the motion path of cannonball. Find the maximum height it can reach, horizontal distance it covers and total time from the given information. The angle between cannonball and horizontal is 53°. V=25m/s ttotal? hmax=? h=60m X=?
Projectile Motion, Constant Accel. Formulas X components (horizontal): projectile: Vx =Vx0 + a,t X = X, + Vxot + ½ a,t? v,? = V,0² + 2a,(x-x) Vy =Vx0 X X = X, + Vxot v,? = v, %D 2 x0 Y components (vertical): projectile: Vy = Vyo + a,t y = yo + Vyot + ½ a,t² v, = v,² + 2a,(y-y.) Vy = Vyo - gt y = yo + Vyot - ½ gt? v, = v,² - 2g(y-yo) = V. = V.
Transcribed Image Text:Projectile Motion, Constant Accel. Formulas X components (horizontal): projectile: Vx =Vx0 + a,t X = X, + Vxot + ½ a,t? v,? = V,0² + 2a,(x-x) Vy =Vx0 X X = X, + Vxot v,? = v, %D 2 x0 Y components (vertical): projectile: Vy = Vyo + a,t y = yo + Vyot + ½ a,t² v, = v,² + 2a,(y-y.) Vy = Vyo - gt y = yo + Vyot - ½ gt? v, = v,² - 2g(y-yo) = V. = V.
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