3. How much energy is released in the fission of 1 kg of 235U according to the equation below? The experimentally determined masses of the products are 136.92532 amu and 96.91095 amu, respectively. (The masses of 235U and neutron are:235.0439231 amu and 1.0086649 amu, respectively.) 137, Те + 235U + on 52 Te 13Zr + 23n 92 4. How many liters of gasoline would have to undergo combustion to provide the same quantity of energy as that released by the fission of one kilogram of 235U to produce 137Te and 97Zr in #3?

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3. How much energy is released in the fission of 1 kg of 235U according to the
equation below? The experimentally determined masses of the products are
136.92532 amu and 96.91095 amu, respectively. (The masses of 235U and
neutron are:235.0439231 amu and 1.0086649 amu, respectively.)
137,
235U + on
52Te + 6Zr + 2½n
13Zr + 23n
4. How many liters of gasoline would have to undergo combustion to provide
the same quantity of energy as that released by the fission of one kilogram
of 235U to produce 137Te and 97Zr in #3?
Transcribed Image Text:3. How much energy is released in the fission of 1 kg of 235U according to the equation below? The experimentally determined masses of the products are 136.92532 amu and 96.91095 amu, respectively. (The masses of 235U and neutron are:235.0439231 amu and 1.0086649 amu, respectively.) 137, 235U + on 52Te + 6Zr + 2½n 13Zr + 23n 4. How many liters of gasoline would have to undergo combustion to provide the same quantity of energy as that released by the fission of one kilogram of 235U to produce 137Te and 97Zr in #3?
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