3. Explain why the relationship between the PlayingCard, Rank and Suit classes is not an is-a relationship. **"Is-a" versus "Has-a"**A large program will often be built out of multiple classes. Often, these classes will have a "has a" relationship. For example, a game program might include three classes: PlayingCard, Suit, and Rank. A PlayingCard object *has a* Suit and *has a* Rank, which are handled in a Java program as instance variables.**Diagram Description:**The diagram is a UML class diagram representing the `PlayingCard` class. It is structured into three main sections: Class Name, Data Fields, and Methods.- **Class Name: PlayingCard** - **Data Fields:** - `cardRank: Rank` - `cardSuit: Suit` - **Methods:** - `setRank(Rank rank): void` - `setSuit(Suit suit): void` - `getRank(): Rank` - `getSuit(): Suit`This diagram shows that the `PlayingCard` class has two instance variables (`cardRank` and `cardSuit`) and four methods (`setRank`, `setSuit`, `getRank`, `getSuit`) for setting and getting the values of these instance variables.---Less often, you might have two classes which have an "is a" relationship, where one class is a more general class, while the second class is a more specialized version of the original class. A blackjack program might have a `BlackJackCard` class which *is a* PlayingCard. Notice the relationship is not symmetrical: every `BlackJackCard` *is a* PlayingCard, but not every PlayingCard *is a* `BlackJackCard`.

3. Whenever one class inherits another class or one interface inherits another interface, it is…

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3. Explain why the relationship between the PlayingCard, Rank and Suit classes is not an is-a relationship.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Enhanced ER Model

The enhanced ER model is an abbreviation for Enhanced Entity-Relationship (EER) model. As you know, the entity-relationship (ER) model is a pictorial illustration of the relationship between various entities of a domain. In the case of a large amount of data with multiple interrelated entities, the ER diagrams become complex and tough to interpret. For such cases, the need for enhancement in the ER model was observed, and thus, the EER model was designed.

Question

3. Explain why the relationship between the PlayingCard, Rank and Suit classes is not an is-a relationship.

**"Is-a" versus "Has-a"**

A large program will often be built out of multiple classes. Often, these classes will have a "has a" relationship. For example, a game program might include three classes: PlayingCard, Suit, and Rank. A PlayingCard object *has a* Suit and *has a* Rank, which are handled in a Java program as instance variables.

**Diagram Description:**

The diagram is a UML class diagram representing the `PlayingCard` class. It is structured into three main sections: Class Name, Data Fields, and Methods.

- **Class Name: PlayingCard**

- **Data Fields:**
- `cardRank: Rank`
- `cardSuit: Suit`

- **Methods:**
- `setRank(Rank rank): void`
- `setSuit(Suit suit): void`
- `getRank(): Rank`
- `getSuit(): Suit`

This diagram shows that the `PlayingCard` class has two instance variables (`cardRank` and `cardSuit`) and four methods (`setRank`, `setSuit`, `getRank`, `getSuit`) for setting and getting the values of these instance variables.

---

Less often, you might have two classes which have an "is a" relationship, where one class is a more general class, while the second class is a more specialized version of the original class. A blackjack program might have a `BlackJackCard` class which *is a* PlayingCard. Notice the relationship is not symmetrical: every `BlackJackCard` *is a* PlayingCard, but not every PlayingCard *is a* `BlackJackCard`.

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