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- 29 29 6. What is the energy released in this ß+ nuclear reaction S →→ 16 that of 29P is 28.9818 u) 15 MeV ssf60 s 29 P+e? (The atomic mass of 20S is 28.996615 u and 16 f60 ssfos 09 ( sf60 ssf1) Complete the reaction: 242Am + ? n → 90Sr + 149La + 4n a) n b) 2n c) 3n d) 4n e) 5n 2) Calculate the energy (in MeV) released in the nuclear fission reaction. The atomic masses are 242Am = 242.059549 u, 90Sr = 89.9077387 u, and 149La = 148.934733 u. (Express your answer to six significant figures).b) What type of decay is happening in the equation below? State two of the conservation laws that apply and explain how they are satisfied 238 92 U 234 Th + 4 a 90 2 c) Use the graph below to calculate the half-life of Protactinium 234, explain how you got your answer. Half Life of Protactinium 234 50 40 30 20 10 222222° 80 70 60 Activity (Bq) 0 20 20 40 40 60 80 100 120 140 160 Time (seconds)