3. Consider the line element of the sphere of radius a: ds² = a² (do² + sin² 0 do²). The only non-vanishing Christoffel symbols are re 00 = - sin cos 0, ГФ 00 = = rø фо 1 tan O' c) The geodesics of the sphere are great circles. Thinking of 0 = 0 as the North pole and = πT as the South pole, find a set a solutions to the geodesic equation corresponding to meridians, and also the solution corresponding to the equator.
3. Consider the line element of the sphere of radius a: ds² = a² (do² + sin² 0 do²). The only non-vanishing Christoffel symbols are re 00 = - sin cos 0, ГФ 00 = = rø фо 1 tan O' c) The geodesics of the sphere are great circles. Thinking of 0 = 0 as the North pole and = πT as the South pole, find a set a solutions to the geodesic equation corresponding to meridians, and also the solution corresponding to the equator.
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
Transcribed Image Text:3. Consider the line element of the sphere of radius a:
ds² = a² (do² + sin² 0 do²).
The only non-vanishing Christoffel symbols are
re
00
=
- sin cos 0,
ГФ
00
=
= rø
фо
1
tan O'
c) The geodesics of the sphere are great circles. Thinking of 0 = 0 as the North pole and = πT
as the South pole, find a set a solutions to the geodesic equation corresponding to meridians, and
also the solution corresponding to the equator.
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