(1 point) A particle moving in simple harmonic motion passes through the equilibrium point, x = 0, 3 times every second. At t = 0 its velocity at x=0.025 m is negative. It travels 0.2m in a complete cycle. The particle's position as a function of time is described by the following function: x(t) = sin( t+ ) cm
(1 point) A particle moving in simple harmonic motion passes through the equilibrium point, x = 0, 3 times every second. At t = 0 its velocity at x=0.025 m is negative. It travels 0.2m in a complete cycle. The particle's position as a function of time is described by the following function: x(t) = sin( t+ ) cm
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![(1 point) A particle moving in simple harmonic motion passes through the equilibrium point, x = 0, 3 times every second. At t = 0 its
velocity at x=0.025 m is negative. It travels 0.2m in a complete cycle.
The particle's position as a function of time is described by the following function:
x(t) =
sin(
t+
) cm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd3b47de9-ab03-46ac-87a3-d1fdc6595c45%2F3ff4dd74-2d77-4e69-9fdd-6198f6bc3656%2F9413q7o_processed.png&w=3840&q=75)
Transcribed Image Text:(1 point) A particle moving in simple harmonic motion passes through the equilibrium point, x = 0, 3 times every second. At t = 0 its
velocity at x=0.025 m is negative. It travels 0.2m in a complete cycle.
The particle's position as a function of time is described by the following function:
x(t) =
sin(
t+
) cm
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