3. Consider the following simple circuit. d) The current flowing in this circuit is constant in time. What does this imply about the speed with which the charge carriers move around the circuit? e) Recall that according to the work-kinetic energy theorem, the net work done on the charge carriers must equal the change in their kinetic energy. Considering your answer from part (d), what is the net work done on the charge carriers as they go around the circuit? a) What is the potential difference between one terminal of the battery and the other? b) Considering your answer from part (a), how much work does it take to bring an element of charge dq from the "bottom" terminal to the "top" terminal? f) We found in part (c) that the battery does positive work on the charge carriers as they move around the circuit. So something else must be doing negative work on the charges as the move around, in order kinetic energy theorem. What element in the circuit is doing negative work on the charges? satisfy the work- c) Considering your answer from part (b), at what rate is the battery doing work on the charges in the circuit? Answer in terms of the symbols on the diagram. g) In order to satisfy the work-kinetic energy theorem, what must be the rate at which heat is lost through the resistor? Answer in terms of the symbols on the diagram. *

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Please answer g only
3. Consider the following simple circuit.
d) The current flowing in this circuit is constant
in time. What does this imply about the speed
with which the charge carriers move around
the circuit?
e) Recall that according to the work-kinetic
energy theorem, the net work done on the
charge carriers must equal the change in their
kinetic energy. Considering your answer from
part (d), what is the net work done on the
charge carriers as they go around the circuit?
E :
a) What is the potential difference between one
terminal of the battery and the other?
b) Considering your answer from part (a), how
much work does it take to bring an element of
charge dq from the "bottom" terminal to the
"top" terminal?
f) We found in part (c) that the battery does
positive work on the charge carriers as they
move around the circuit. So something else
must be doing negative work on the charges as
the move around, in order to satisfy the work-
kinetic energy theorem. What element in the
circuit is doing negative work on the charges?
c) Considering your answer from part (b), at
what rate is the battery doing work on the
charges in the circuit? Answer in terms of the
symbols on the diagram.
g) In order to satisfy the work-kinetic energy
theorem, what must be the rate at which heat
is lost through the resistor? Answer in terms
of the symbols on the diagram. *
Transcribed Image Text:3. Consider the following simple circuit. d) The current flowing in this circuit is constant in time. What does this imply about the speed with which the charge carriers move around the circuit? e) Recall that according to the work-kinetic energy theorem, the net work done on the charge carriers must equal the change in their kinetic energy. Considering your answer from part (d), what is the net work done on the charge carriers as they go around the circuit? E : a) What is the potential difference between one terminal of the battery and the other? b) Considering your answer from part (a), how much work does it take to bring an element of charge dq from the "bottom" terminal to the "top" terminal? f) We found in part (c) that the battery does positive work on the charge carriers as they move around the circuit. So something else must be doing negative work on the charges as the move around, in order to satisfy the work- kinetic energy theorem. What element in the circuit is doing negative work on the charges? c) Considering your answer from part (b), at what rate is the battery doing work on the charges in the circuit? Answer in terms of the symbols on the diagram. g) In order to satisfy the work-kinetic energy theorem, what must be the rate at which heat is lost through the resistor? Answer in terms of the symbols on the diagram. *
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