3. Cobalt (II) Sulfide (CoS) is more soluble in aqueous solutions when you add an inert salt like potassium nitrate, even though neither potassium nor nitrate show up in the BCE for the dissolution reaction. The solubility product constant for cobalt (II) sulfide is Ksp = 5 x 10-22 making it a remarkably insoluble substance. Your job is to figure out the molar solubility in pure water, then the molar solubility in a 0.25 M KNO3 aqueous solution and finally to express the change as a percent difference. To make it easier (and faster) please use the Debye-Hückel limiting law: log Yx = -0.510 Zx² (u)1/2 to obtain the required activity coefficients and make a simple assumption about the ionic strength of water - rather than solving for it in an iterative process.

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Chapter1: Chemical Foundations
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3. Cobalt (II) Sulfide (CoS) is more soluble in aqueous solutions when you add
an inert salt like potassium nitrate, even though neither potassium nor nitrate
show up in the BCE for the dissolution reaction.
The solubility product constant for cobalt (II) sulfide is Ksp = 5 x 10-22 making it a
remarkably insoluble substance. Your job is to figure out the molar solubility in
pure water, then the molar solubility in a 0.25 M KNO3 aqueous solution and
finally to express the change as a percent difference. To make it easier (and faster)
please use the Debye-Hückel limiting law: log Yx = -0.510 Zx2² (μ)1/2 to obtain the
required activity coefficients and make a simple assumption about the ionic
strength of water - rather than solving for it in an iterative process.
Transcribed Image Text:3. Cobalt (II) Sulfide (CoS) is more soluble in aqueous solutions when you add an inert salt like potassium nitrate, even though neither potassium nor nitrate show up in the BCE for the dissolution reaction. The solubility product constant for cobalt (II) sulfide is Ksp = 5 x 10-22 making it a remarkably insoluble substance. Your job is to figure out the molar solubility in pure water, then the molar solubility in a 0.25 M KNO3 aqueous solution and finally to express the change as a percent difference. To make it easier (and faster) please use the Debye-Hückel limiting law: log Yx = -0.510 Zx2² (μ)1/2 to obtain the required activity coefficients and make a simple assumption about the ionic strength of water - rather than solving for it in an iterative process.
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