0.1 gram of solid aluminum phosphate (Al(PO.) (s) is added to 500 L of pure water. Immediately the solid begins to dissolve according to the reactions below. Complete dissolution: Al(PO.) (s) → Al+ PO, No K Solid present: Al(PO.) (5) + Al* + PO; Ksp = 1012 What is the concentration of dissolved phosphate (in M and mg/L) in the water once all reactions proceed to completion? Is the solid still present or has it completely dissolved? Why or why not? If the solid is present, calculate the solid concentration (in M and mg/L). Develop a plot showing the aqueous (dissolved) concentration of PO: (in M) on the Y-axis versus different AlI(PO:)

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**Educational Explanation of Aluminum Phosphate Dissolution**

When 0.1 gram of solid aluminum phosphate (Al(PO₄)₍ₛ₎) is added to 500 liters of pure water, it starts dissolving according to the following reactions:

1. **Complete Dissolution:**
   - Reaction: Al(PO₄)₍ₛ₎ → Al³⁺ + PO₄³⁻
   - Note: No equilibrium constant (K) is specified because this reaction assumes complete dissolution.

2. **Equilibrium with Solid Present:**
   - Reaction: Al(PO₄)₍ₛ₎ ⇌ Al³⁺ + PO₄³⁻
   - Solubility Product Constant (Ksp): \( 10^{-12} \)

**Questions for Consideration:**

- **Concentration of Dissolved Phosphate:** Determine the concentration of phosphate ions (PO₄³⁻) in molarity (M) and milligrams per liter (mg/L) once the system reaches equilibrium. Assess whether the solid persists or is entirely dissolved. Use reasoning to support your conclusion.
  
- **Solid Concentration Calculation:** If the solid remains, calculate its concentration in both molarity (M) and milligrams per liter (mg/L).

**Plot Development:**

- **Graphical Representation:** Create a graph illustrating the concentration of dissolved PO₄³⁻ (in M) on the Y-axis against various initial concentrations of Al(PO₄)₍ₛ₎ (in M) on the X-axis.
  
- **Critical Point Identification:** Indicate the critical point on the graph that distinguishes between complete dissolution of the solid and the presence of residual solid. Label this point clearly.

This educational content delves into the concept of solubility equilibrium, promoting understanding of chemical equilibria and the factors influencing solubility.
Transcribed Image Text:**Educational Explanation of Aluminum Phosphate Dissolution** When 0.1 gram of solid aluminum phosphate (Al(PO₄)₍ₛ₎) is added to 500 liters of pure water, it starts dissolving according to the following reactions: 1. **Complete Dissolution:** - Reaction: Al(PO₄)₍ₛ₎ → Al³⁺ + PO₄³⁻ - Note: No equilibrium constant (K) is specified because this reaction assumes complete dissolution. 2. **Equilibrium with Solid Present:** - Reaction: Al(PO₄)₍ₛ₎ ⇌ Al³⁺ + PO₄³⁻ - Solubility Product Constant (Ksp): \( 10^{-12} \) **Questions for Consideration:** - **Concentration of Dissolved Phosphate:** Determine the concentration of phosphate ions (PO₄³⁻) in molarity (M) and milligrams per liter (mg/L) once the system reaches equilibrium. Assess whether the solid persists or is entirely dissolved. Use reasoning to support your conclusion. - **Solid Concentration Calculation:** If the solid remains, calculate its concentration in both molarity (M) and milligrams per liter (mg/L). **Plot Development:** - **Graphical Representation:** Create a graph illustrating the concentration of dissolved PO₄³⁻ (in M) on the Y-axis against various initial concentrations of Al(PO₄)₍ₛ₎ (in M) on the X-axis. - **Critical Point Identification:** Indicate the critical point on the graph that distinguishes between complete dissolution of the solid and the presence of residual solid. Label this point clearly. This educational content delves into the concept of solubility equilibrium, promoting understanding of chemical equilibria and the factors influencing solubility.
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