3. Chi square tests can be used to support or reject other types of hypotheses where random For example, studies done on honeybees may track how often bees visit each type of flower. In these studies, you are trying to disprove that the bees visit the flowers in equal amounts (showed no preference). Scientists observed that 54 bees visited tulips and 66 bees visited lilies. Do the bees in the study below show a statistically significant preference for lilies? (Observed - Expected)? Expected Observed Expected Visited Tulips Visited Lilies Summed X =
3. Chi square tests can be used to support or reject other types of hypotheses where random For example, studies done on honeybees may track how often bees visit each type of flower. In these studies, you are trying to disprove that the bees visit the flowers in equal amounts (showed no preference). Scientists observed that 54 bees visited tulips and 66 bees visited lilies. Do the bees in the study below show a statistically significant preference for lilies? (Observed - Expected)? Expected Observed Expected Visited Tulips Visited Lilies Summed X =
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
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Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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![3. Chi square tests can be used to support or reject other types of hypotheses where random chance can be involved.
For example, studies done on honeybees may track how often bees visit each type of flower. In these studies, you are
trying to disprove that the bees visit the flowers in equal amounts (showed no preference). Scientists
observed that 54 bees visited tulips and 66 bees visited lilies.
Do the bees in the study below show a statistically significant preference for lilies?
(Observed - Expected)?
Expected
Observed
Expected
Visited Tulips
Visited Lilies
Summed X =
ANALYSIS:
4. In Wisconsin Fast plants, purple stems (P) are dominant to green stems (p). Plants can also be tall (T) or
dwarf (t). Two tall plants with purple stems are crossed with results shown in the chart. Do the results
support a hypothesis that both plants were heterozygous? Show a chi square analysis to support your
position.
(Observed - Expected)?
Expected
Observed
Expected
Purple, tall
48
Purple, dwarf
16
Green, tall
12
Green, dwarf
6.
Summed X = 1.011 (good fit)
ANALYSIS:
z* critical values
probability
(0-e)
X² =E
df
.995
.90
50
10
05
025
2.706 3.841
5.024
.455
1.386
2.366 6.251
.207 1.064 3.357 7.779 9.488 11.143
.000
.016
.010 .211
.072 .584
2
4.605 5.991
7.378
e
3
7.815 9.348
4
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Transcribed Image Text:3. Chi square tests can be used to support or reject other types of hypotheses where random chance can be involved.
For example, studies done on honeybees may track how often bees visit each type of flower. In these studies, you are
trying to disprove that the bees visit the flowers in equal amounts (showed no preference). Scientists
observed that 54 bees visited tulips and 66 bees visited lilies.
Do the bees in the study below show a statistically significant preference for lilies?
(Observed - Expected)?
Expected
Observed
Expected
Visited Tulips
Visited Lilies
Summed X =
ANALYSIS:
4. In Wisconsin Fast plants, purple stems (P) are dominant to green stems (p). Plants can also be tall (T) or
dwarf (t). Two tall plants with purple stems are crossed with results shown in the chart. Do the results
support a hypothesis that both plants were heterozygous? Show a chi square analysis to support your
position.
(Observed - Expected)?
Expected
Observed
Expected
Purple, tall
48
Purple, dwarf
16
Green, tall
12
Green, dwarf
6.
Summed X = 1.011 (good fit)
ANALYSIS:
z* critical values
probability
(0-e)
X² =E
df
.995
.90
50
10
05
025
2.706 3.841
5.024
.455
1.386
2.366 6.251
.207 1.064 3.357 7.779 9.488 11.143
.000
.016
.010 .211
.072 .584
2
4.605 5.991
7.378
e
3
7.815 9.348
4
www hinlogvrorner com
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