please help with question d and help me fill in the table. d. Calculate the observed frequencies of genotypes C°C°, C°C', and C'C" at day 7. Fillin the table below; enter your answers to two decimal places.C°C©C°C"C'CDay 7 observedgenotype frequencies 9. A farmer is testing whether a soybean population is evolving at a locus with two alleles,C and C', that affect chlorophyll production and leaf color. Students planted soybeanseeds and then counted the number of seedlings of each genotype at day 7 and again atday 21. Seedlings of each genotype could be distinguished visually because the C and Calleles show incomplete dominance: C°C° seedlings have green leaves, C°C' seedlingshave green-yellow leaves, and C'c' seedlings have yellow leaves.Number of seedlings of each genotypeTime (days)Green (C°C)Green-yellow (CC")Yellow (C'C')Total4911156216214710620173

Question - Calculate the observed frequencies of genotypes CGCG , CGCY and CYCY at day 7. Fill in the table below; enter your answers to two decimal places.Answer - Step 1; Calculate observed genotype frequencies at day 7 and day 21 A) At day 7 Observed genotype frequency at day 7 for CGCG = 49/216 = 0.227 Observed genotype frequency at day 7 for CGCY = 0.514 Observed genotype frequency at day 7 for CYCY = 56 / 216 = 0.259 b) At day 21 Observed genotype frequency at day 21 for CGCG = 47/173 0.272 Observed genotype frequency at day 21 for CGCY106 = 0.613 Observed genotype frequency at day 21 for CYCY = 0.116 Step 2: Calculate expected genotype frequencies at day 21 [Let frequency of CG allele be represented by 'p' and frequency of CY allele be represented by 'q'] a) At day 7 p = all CG alleles / total alleles = 49 +49 + 111/49 +49 + 111 + 111 +56 +56= 0.484 q = all CY alleles / total alleles = 56 +56 + 111/49 +49 + 111 + 111 + 56+ 56 = 0.516 Expected genotype frequency at day 7 for CGCG = p2 = (0.484)2 = 0.234 Expected genotype frequency at day 7 for CYCY = q2 = (0.516)2 = 0.266 Expected genotype frequency at day 7 for CGCY =2pq = 2 x 0.484 x 0.516 = 0.500 a) At day 21 p = all CG alleles / total alleles = 47 +47 + 106/47 +47 + 106 + 106+ 20+ 20 = 0.578 q = all CY alleles / total alleles = 20 + 20 + 106 / 47+47 + 106 + 106 + 20+ 20 = 0.422 Expected genotype frequency at day 21 for CGCG = p2 = (0.578)2 = 0.334 Expected genotype frequency at day 21 for CYCY =q2 = (0.422)2 = 0.178 Expected genotype frequency at day 21 for CGCY = 2pq = 2 x 0.578 x 0.422 = 0.487 Step 3: Compare observed / expected frequencies at day 7 and 21, to find genotype frequencies in HardyWeinberg Equillibrium On comparision, we can see that expected genotype frequencies at day 7 are in close proximity to observed genotype frequencies i.e. population at day 7 are Hardy-Weinberg Equillibrium. Answer: Expected frequency of CGCG = 0.234 CGCY =0.500 CYCY = 0.266