3. Calculate the equilibrium constant for the following reaction using the pKa values given, and circle the correct answer among the choices (a)- (d) shown below. Keq ill = lei + Keq = (a) 10-11 pka=9 or (b) pka = 20 10¹1 or (c) 1029 or (d) 10-29

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**Problem 3: Calculation of Equilibrium Constant Using pKa Values**

Calculate the equilibrium constant for the following reaction using the pKa values given, and circle the correct answer among the choices (a) – (d) shown below.

**Reaction Scheme:**

- Left side:
  - Structure 1: A deprotonated acetone molecule (acetone enolate anion) with a negative charge on the oxygen.
  - Structure 2: Acetylacetone molecule with a pKa value of 9.

- Right side:
  - Structure 3: Acetone molecule with a pKa value of 20.
  - Structure 4: A deprotonated acetylacetone molecule (acetylacetone enolate anion) with a negative charge on the oxygen.

**Equilibrium:**
- The reaction is reversible, denoted by a double-headed arrow labeled as Keq.

**Choices for Keq:**

- (a) \(10^{11}\)
- (b) \(10^{-11}\)
- (c) \(10^{29}\)
- (d) \(10^{-29}\)
Transcribed Image Text:**Problem 3: Calculation of Equilibrium Constant Using pKa Values** Calculate the equilibrium constant for the following reaction using the pKa values given, and circle the correct answer among the choices (a) – (d) shown below. **Reaction Scheme:** - Left side: - Structure 1: A deprotonated acetone molecule (acetone enolate anion) with a negative charge on the oxygen. - Structure 2: Acetylacetone molecule with a pKa value of 9. - Right side: - Structure 3: Acetone molecule with a pKa value of 20. - Structure 4: A deprotonated acetylacetone molecule (acetylacetone enolate anion) with a negative charge on the oxygen. **Equilibrium:** - The reaction is reversible, denoted by a double-headed arrow labeled as Keq. **Choices for Keq:** - (a) \(10^{11}\) - (b) \(10^{-11}\) - (c) \(10^{29}\) - (d) \(10^{-29}\)
Expert Solution
Step 1

The acid dissociation equation for pKa = 9 and pKa = 20 are:

Chemistry homework question answer, step 1, image 1

pKa = 9 (or) Ka = 10-pKa = 1x10-9 

pKa = 20 (or) Ka = 10-pKa = 1x10-20 

 

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