3. Calculate the equilibrium constant for the following reaction using the pKa values given, and circle the correct answer among the choices (a)- (d) shown below. Keq ill = lei + Keq = (a) 10-11 pka=9 or (b) pka = 20 10¹1 or (c) 1029 or (d) 10-29
3. Calculate the equilibrium constant for the following reaction using the pKa values given, and circle the correct answer among the choices (a)- (d) shown below. Keq ill = lei + Keq = (a) 10-11 pka=9 or (b) pka = 20 10¹1 or (c) 1029 or (d) 10-29
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please answer this question with explanation! thank you!
![**Problem 3: Calculation of Equilibrium Constant Using pKa Values**
Calculate the equilibrium constant for the following reaction using the pKa values given, and circle the correct answer among the choices (a) – (d) shown below.
**Reaction Scheme:**
- Left side:
- Structure 1: A deprotonated acetone molecule (acetone enolate anion) with a negative charge on the oxygen.
- Structure 2: Acetylacetone molecule with a pKa value of 9.
- Right side:
- Structure 3: Acetone molecule with a pKa value of 20.
- Structure 4: A deprotonated acetylacetone molecule (acetylacetone enolate anion) with a negative charge on the oxygen.
**Equilibrium:**
- The reaction is reversible, denoted by a double-headed arrow labeled as Keq.
**Choices for Keq:**
- (a) \(10^{11}\)
- (b) \(10^{-11}\)
- (c) \(10^{29}\)
- (d) \(10^{-29}\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa451162e-14ac-4cfd-a2c6-1eae7f4a5f1a%2F6c176388-a08b-4621-832e-836dd80d363e%2Fbm25tjg_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem 3: Calculation of Equilibrium Constant Using pKa Values**
Calculate the equilibrium constant for the following reaction using the pKa values given, and circle the correct answer among the choices (a) – (d) shown below.
**Reaction Scheme:**
- Left side:
- Structure 1: A deprotonated acetone molecule (acetone enolate anion) with a negative charge on the oxygen.
- Structure 2: Acetylacetone molecule with a pKa value of 9.
- Right side:
- Structure 3: Acetone molecule with a pKa value of 20.
- Structure 4: A deprotonated acetylacetone molecule (acetylacetone enolate anion) with a negative charge on the oxygen.
**Equilibrium:**
- The reaction is reversible, denoted by a double-headed arrow labeled as Keq.
**Choices for Keq:**
- (a) \(10^{11}\)
- (b) \(10^{-11}\)
- (c) \(10^{29}\)
- (d) \(10^{-29}\)
Expert Solution
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Step 1
The acid dissociation equation for pKa = 9 and pKa = 20 are:
pKa = 9 (or) Ka = 10-pKa = 1x10-9
pKa = 20 (or) Ka = 10-pKa = 1x10-20
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