3. An ideal gas with Cv = 1.62 kJ/kg-K and R = 273J/kg-K expands from 0.15 m3 and 27°C to 0.35 m³ during an isobaric process with p = 150kPa. Consider the process reversible nonflow, determine (a) the heat, (b) the change in internal energy, (c) the change in entropy. Answers: 208KJ; 178KJ; 30kJ
3. An ideal gas with Cv = 1.62 kJ/kg-K and R = 273J/kg-K expands from 0.15 m3 and 27°C to 0.35 m³ during an isobaric process with p = 150kPa. Consider the process reversible nonflow, determine (a) the heat, (b) the change in internal energy, (c) the change in entropy. Answers: 208KJ; 178KJ; 30kJ
Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Note: The answer is given on the bottom side of the image, just show the solution on how to get it.
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
Transcribed Image Text:3. An ideal gas with Cv = 1.62 kJ/kg-K and R = 273J/kg-K expands from 0.15 m3
and 27°C to 0.35 m³ during an isobaric process with p = 150kPa. Consider the
process reversible nonflow, determine (a) the heat, (b) the change in internal
energy, (c) the change in entropy.
Answers: 208KJ; 178KJ; 30kJ
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