ready to move. Pick a mass of the object and one typeof surface and record them. Mass (M)Surface type =kg,. Then click to start andkeep observing force applied in lab quest. When objectshows a kink means ready to move, check value offorce, that is the force when it is equal to static frictionforce. It is the maximum value of force that appears inthe screen and graph as maximum value of force.Record its value from graph. Fs (static max) = _ NKeep looking the lab quest and see when the value offorce drops from its maximum value,

The image you sent appears to be a lab instruction that deals with static friction.The text in the…

Answered: ready to move. Pick a mass of the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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No need guideline answer ok. Solve both write RRL. ABOUT THESE 2 ITEMS. NOTE NO NEED EXTRA EXPLANATION ONLY NEED FOR OTH 1 PARAGRAPH EACH PUT REF END POINTS OK. DONT NEED GUIDELINE OKK. IF ANSWER GUIDELINE I WILL DISLIKE OKK 1. height of sweet potato plants; 2. programable speed of a rover: . something that says that a rover is programmed via speed, that it doesn't matter if the weight of the rover is decreasing from time to time. something that says that if you programmed a rover to go 5kph it will remain 5kph even if you put something heavy on it.
I am attaching both questions for 4 and 5 with the question in the image. thank you. NOTE : So the last person answered this question WITHOUT refencing the answer for whether question 4 or 5 answeres were given, so i am asking for question 5(or the answer for the question that was NOT solved because it was not referenced.) These were the following answers given to me from the last person on bartleby who answered my question without referencing whether it was the answer for question 4 or 5. 1 pass 2 fail 3 fail 4 pass
Pls help ASAP
1) A low-friction cart is placed between two identical springs attached to rigid walls. If you push the cart against one of the springs and release it, it will continue to move back and forth between the springs. www Draw a force-time graph showing the sum of the horizontal forces exerted on the cart as it moves back and force between the springs. Scientific Abilities Is able to construct a force diagram Missing No representation is constructed. Inadequate FD is constructed but contains major errors such as incorrect mislabeled or not labeled force vectors, length of vectors, wrong direction, extra incorrect vectors are added, or vectors are missing. Needs Improvement FD contains no errors in vectors but lacks a key feature such as labels of forces with two subscripts or vectors are not drawn from single point, or axes are missing. Adequate The diagram contains no errors and each force is labeled so that it is clearly understood what each force represents. Explain whether or not this…
Use the attached graph to answer the follwing questions a. Write an equation that gives the position with respect to time (use specific quantities) b. Write an equation that gives the velocity with respect to time (use specific quantities) c. Draw a velocity over time graph for this motion from t=0 to t=12s.
2. Complete the table. This problem involves the power required to raise a mass a given distance in a given amount of time. (Round your answers for mass and energy to the nearest whole number.) (Round your answers for power to two decimal places.) 3 Click the icon to view the table to complete. 4 Click the icon to view the conversion table. 5 Click the icon to view the table of common derived units in the Sl system. 3: More Info 4: More Info 2 11 Q W (a) (b) (a) (b) Mass [bm] 220 Time 1 d = 24 h 1 h = 60 min Mass [Ibm 1 min = 60 s 3 1 yr = 365 d E 220 $ 4 Distance [ft] 1 kg = 1 slug = 14.5939 kg 1 slug = 32.2 lbm 15 Distance [ft] 15 35 Mass 2.205 lbm I R 35 % 5 I T Energy [J] Length 1 m = 3.28 ft 1 km = 0.621 mi 1 in = 2.54 cm 1 mi = 5,280 ft Energy [J] ^ 6 MacBook Pro Y & 7 Time [min] Energy 1 J = 0.239 cal = 9.48 x 10-4 BTU = 0.7376 ft lbf 1 kWh 3,600,000 J H 0.5 Time [min] 0.5 2 2 8 1 ( 20 Power [hp] 0.134 Power [hp] 0.134 Power 1 W 3.412 BTU/h = 0.00134 hp = 14.34 cal/min = 0.7376…
Need correctly all parts

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