A Tesla car has a battery that can hold from 50 kWh to 75 kWh of stored energy. (1 kWh = 1000 W x 3600 sec = 1000 J/sec x 3600 sec = 3,600,000 J). 1) How much energy is 1 kWh compared to the energy released when burning 1 gallon of gasoline? A Tesla has a range of about 300 to 400 miles on a full battery. So let us assume that a Tesla with a 50 kWh battery can go 300 miles. Also assume that 1 kWh cost 25 cents to produce. 2) Calculate how much it costs to drive a Tesla 40 miles 3) Calculate how much gas (in gallons) you can buy with the cost of driving a Tesla 40 miles (the results will most likely be a fraction of a gallon) 4) Calculate the advertised "gas mileage" of a Tesla. (for example if the cost of driving a tesla 40 miles is $2.50 and a gallon of gas costs $5 then a Tesla can drive 40 miles on a "half gallon of gas", and therefore gets 80 miles on "a gallon of gas"). 5) To get the "equivalent gas mileage" for a Tesla we need to %3D determine the amount of energy used by the car to cover a given distance and compare that to the energy in a gallon of gas. Thus if a Tesla can cover 300 miles with 50 kWh of then the Tesla can cover 6 miles with 1 kWh of energy, energy. By equating the energy of 1 gal of gas (120 million Joules) to the energy of 1 kWh, convert 6 miles per kWh into miles per gallon. (That is another method to come up with the advertised "gas mileage" of a Tesla). 6) The transmission of battery energy to car motion in an electric car is fairly efficient, but the inefficiency of the power plant energy production is ignored. The efficiency of a power plant is about 35%. To get the true "gas mileage equivalent" of a Tesla we must take the results calculated in part 5 and multiply it by the 35 % efficiency. Compare your results with a gasoline car that gets 40 miles to the gallon.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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A Tesla car has a battery that can hold from 50 kWh to 75 kWh
of stored energy. (1 kWh = 1000 W x 3600 sec = 1000 J/sec x
3600 sec = 3,600,000 J).
1) How much energy is 1 kWh compared to the
released when burning 1 gallon of gasoline?
A Tesla has a range of about 300 to 400 miles on a full battery.
So let us assume that a Tesla with a 50 kWh battery can go 300
miles. Also assume that 1 kWh cost 25 cents to produce.
2) Calculate how much it costs to drive a Tesla 40 miles
3) Calculate how much gas (in gallons) you can buy with the
cost of driving a Tesla 40 miles
(the results will most likely be a fraction of a gallon)
4) Calculate the advertised “gas mileage" of a Tesla. (for
example if the cost of driving a tesla 40 miles is $2.50 and
a gallon of gas costs $5 then a Tesla can drive 40 miles on a
“half gallon of gas", and therefore gets 80 miles on "a
gallon of gas").
5) To get the "equivalent gas mileage" for a Tesla we need to
energy
determine the amount of energy used by the car to cover a
given distance and compare that to the energy in a gallon of
gas. Thus if a Tesla can cover 300 miles with 50 kWh of
energy, then the Tesla can cover 6 miles with 1 kWh of
energy. By equating the energy of 1 gal of gas (120 million
Joules) to the energy of 1 kWh, convert 6 miles per kWh
into miles per gallon. (That is another method to come up
with the advertised "gas mileage" of a Tesla).
6) The transmission of battery energy to car motion in an
electric car is fairly efficient, but the inefficiency of the
power plant energy production is ignored. The efficiency
of a power plant is about 35%. To get the true “gas mileage
equivalent" of a Tesla we must take the results calculated in
5 and multiply it by the 35 % efficiency. Compare
part
your results with a gasoline car that gets 40 miles to the
gallon.
Transcribed Image Text:A Tesla car has a battery that can hold from 50 kWh to 75 kWh of stored energy. (1 kWh = 1000 W x 3600 sec = 1000 J/sec x 3600 sec = 3,600,000 J). 1) How much energy is 1 kWh compared to the released when burning 1 gallon of gasoline? A Tesla has a range of about 300 to 400 miles on a full battery. So let us assume that a Tesla with a 50 kWh battery can go 300 miles. Also assume that 1 kWh cost 25 cents to produce. 2) Calculate how much it costs to drive a Tesla 40 miles 3) Calculate how much gas (in gallons) you can buy with the cost of driving a Tesla 40 miles (the results will most likely be a fraction of a gallon) 4) Calculate the advertised “gas mileage" of a Tesla. (for example if the cost of driving a tesla 40 miles is $2.50 and a gallon of gas costs $5 then a Tesla can drive 40 miles on a “half gallon of gas", and therefore gets 80 miles on "a gallon of gas"). 5) To get the "equivalent gas mileage" for a Tesla we need to energy determine the amount of energy used by the car to cover a given distance and compare that to the energy in a gallon of gas. Thus if a Tesla can cover 300 miles with 50 kWh of energy, then the Tesla can cover 6 miles with 1 kWh of energy. By equating the energy of 1 gal of gas (120 million Joules) to the energy of 1 kWh, convert 6 miles per kWh into miles per gallon. (That is another method to come up with the advertised "gas mileage" of a Tesla). 6) The transmission of battery energy to car motion in an electric car is fairly efficient, but the inefficiency of the power plant energy production is ignored. The efficiency of a power plant is about 35%. To get the true “gas mileage equivalent" of a Tesla we must take the results calculated in 5 and multiply it by the 35 % efficiency. Compare part your results with a gasoline car that gets 40 miles to the gallon.
Energy is described as a term that refers to the capacity to do the work. Energy comes in various
forms, including potential energy, kinetic energy, thermal energy, nuclear energy and so on. The
pace at which energy is transferred in relation to time is referred to as power. In this question, the
amount of gasoline can be used to travel the number of miles. Energy conservation is defined as
reducing the consumption of energy by producing or using less of it.
Step 2
Given data:
*The energy store is 50 kWh to 75 kWh.
*The range of the battery is 300 miles to 400 miles
Step 3
(1)
The energy contained in 1 gallon of gasoline is given as,
El gal = 1.2 x 10% J
The relation between 1 kWh and a gallon of gasoline is,
f=L2x10"
3.6x10"
=33. 33
Thus, one gallon of gasoline is 33.33 kWh of enenrgy.
Step 4
(2)
The expression for the energy consumed is given as,
40 miles
E=
300 miles
x 50 kWh
=6. 66 kWh
The price of the energy can be calculated as,
P=6, 66 x 25 cent
=166. 67 cents
=1.67$
Step 5
(3)
The cost of a gallon of gasoline rounds 3.75$.
The amount of gallons of gas to be brought with 1.65$ is,
1.65$
V%=
3.75S/ gallon
=0.44 gallon
Transcribed Image Text:Energy is described as a term that refers to the capacity to do the work. Energy comes in various forms, including potential energy, kinetic energy, thermal energy, nuclear energy and so on. The pace at which energy is transferred in relation to time is referred to as power. In this question, the amount of gasoline can be used to travel the number of miles. Energy conservation is defined as reducing the consumption of energy by producing or using less of it. Step 2 Given data: *The energy store is 50 kWh to 75 kWh. *The range of the battery is 300 miles to 400 miles Step 3 (1) The energy contained in 1 gallon of gasoline is given as, El gal = 1.2 x 10% J The relation between 1 kWh and a gallon of gasoline is, f=L2x10" 3.6x10" =33. 33 Thus, one gallon of gasoline is 33.33 kWh of enenrgy. Step 4 (2) The expression for the energy consumed is given as, 40 miles E= 300 miles x 50 kWh =6. 66 kWh The price of the energy can be calculated as, P=6, 66 x 25 cent =166. 67 cents =1.67$ Step 5 (3) The cost of a gallon of gasoline rounds 3.75$. The amount of gallons of gas to be brought with 1.65$ is, 1.65$ V%= 3.75S/ gallon =0.44 gallon
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