Answered: 3. A stationary 827.76-g object is… | bartleby

Related questions

Question

100%

3. A stationary 827.76-g object is struck by a stick. The object experiences a horizontal
force given by F = a t^½ - b t^-½, where t is the time in milliseconds from the instant the
stick first contacts the object. If a = 872 N/(ms)^½ and b = -84.7 N/(ms)^-½, what is the
speed of the object just after it comes away from the stick at t = 873.7 us?
%3D

Expert Solution

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

At the Earth's surface, a projectile is launched straight up at a speed of 7.7 km/s. To what height will it rise? Ignore air resistance. 3.00E6 X Your response differs from the correct answer by more than 10%. Double check your calculations. m Need Help? Read It
The force shown in the figure(Figure 1) acts on a 1.3-kg object whose initial speed is 0.35 m/s and initial position is x=0.27m. a. Find the speed of the object when it is at the location x=0.99 m. b. At what location would the object's speed be 0.25 m/s?
How does kinetic energy depend on velocity? The kinetic energy is an absolute quantity, the same seen by any observer, moving or stationary. The kinetic energy seen in my reference frame depends on the velocity squared as I would measure it. The kinetic energy increases in proportion to the velocity, so if the velocity doubles the energy doubles. The kinetic energy is zero unless there is an applied force.
The roadrunner has a mass of 25.0 kg. He runs around the desert valley at 3.00 m/s. What is his kinetic energy A J
3. As a 2.0-kg object moves from 21+ 5j ]m to ( 6i – 21 )m, 21+ 5j ]m to 6i – 2j m, the constant resultant force acting on it 3. As a 2.0-kg object moves from is equal to 4i - 3j ]N. If the speed of the object at the initial position is 4.0 m/s, what is its kinetic energy at its final position? se
4. The power provided by a force can also be written as P = dW /dt = F · d7/dt = F .ö. A force F = (3i – 2j + 6k)N is applied to an object moving with a velocity i = (2î – 3k) m/s. a. What is the power provided by this force? Does the object speed up or slow down or neither, if this force is the only unbalanced force acting on the object? b. Consider a force that is always perpendicular to the velocity. Does the object speed up or slow down or neither, if this force is the only unbalanced force acting on the object?
! & OD. Mass 2M and speed 3V O E. Mass 3M and speed V *. 60 QUESTION 2 OA. Mass 3M and speed 2V Which of the following bodies has the largest kinetic energy? OB. Mass M and speed 4V OC. All four of the above have the same kinetic energy OA. 4.85 km/h and 39.8⁰ OB. 3.11 km/h and 39.8⁰ OC.3.73 km/h and 39.8⁰ OD.7.80 km/h and 39.8⁰ OE. 6.20 km/h and 39.8⁰ Two skaters collide and embrace in a completely inelastic collision. Alfred, with mass 83.0 kg, is originally moving east with speed 6.20 kmh. Barbara, with mass 55.0 MacBook UESTION 1 tion Status: are stuck kg, is originally moving north with speed 7.80 km/h. Find the magnitude and direction (with respect to +x direction) of the velocity of the couple after collision when they
16. A 20 000-kg meteorite from outer space is headed directly toward Earth with a speed of 3.0 km/s. Find its speed when it is 200 km above Earth's surface.
5. As a driver steps on the gas petal, a car of mass 1160 kg accelerates from rest. During the first few seconds of motion, the car's acceleration increases with time according to the expression a = 1.16+ - 0.210+2 + 0.240+³, where t is in seconds and a is in meters/sec². (a) What is the change in kinetic energy of the car during the time interval between + = 0 sec and t = 2.5 sec? (b) What is the minimum average power output of the engine over this time interval?, (c) Why is the value in part (b) described as the minimum value?
An object travels at a speed of 4.0 m/s. It has 24 J of kinetic energy. What is the kinetic energy of the object if the speed is 2.0 m/s?a) 6J b) 12J c) 24J d) 48J e) 96J
On the roller-coaster shown, a car is moving 10 m/s toward the right at point 1. Assuming no friction, calculate the speed of the car at point 4. 3 40 m 26 m 15 m 29.37 m/s 22.71 m/s 20.89 m/s 26.17 m/s A. D. В. 25.07 m/s Е. С. 24.29 m/s F.
A particle of mass m has a velocity of v = (v₂i + vj + v₂k). What is the correct expression for its kinetic energy? O a. O b. O c. O d. O e. m(v2i+vy²j + v₂²k)/2 None of these choices. m(vx2 + Vy² + V₂²)/2 m/2(2vx + 2Vy + 2V₂) m/2(2v,i + 2vj + 2v₂k)

SEE MORE QUESTIONS