3. A researcher is interested in knowing if preterm infants with late metabolic acidosis and preterm infants without the condition differ with respect to urine levels of a certain chemical. The mean levels, standard deviations, and sample sizes from the two samples are given below. Assuming that the populations have equal variances: ttesti 38 8.5 3.5 32 6.85 2.6 a. Fill in the missing pieces of the Stata output. Two-sample t test with A variances X y combined diff Obs Ho: diff = 0 38 32 Sample With condition Without condition 70 diff mean(x) Ha: diff < 0 Pr(Tt) = 0.9845 Mean 8.5 6.85 7.745714 C n 38 32 mean(y) .567775 B mean 8.5 6.85 Std. Err. Std. Dev. [95% Conf. Intervall 3834311 D S 3.5 2.6 3.5 2.6 3.208015 Ha: diff != 0 Pr(|T| > |t|) = F 7.349579 5.9126 6.98079 .1552544 degrees of freedom = 9.650421 7.7874 8.510638 3.144746 t = E 68 Ha: diff> 0 Pr(Tt) = 0.0155 b. What is the conclusion of your test? c. Use this output to construct a 99% confidence interval for the difference between the two means.
3. A researcher is interested in knowing if preterm infants with late metabolic acidosis and preterm infants without the condition differ with respect to urine levels of a certain chemical. The mean levels, standard deviations, and sample sizes from the two samples are given below. Assuming that the populations have equal variances: ttesti 38 8.5 3.5 32 6.85 2.6 a. Fill in the missing pieces of the Stata output. Two-sample t test with A variances X y combined diff Obs Ho: diff = 0 38 32 Sample With condition Without condition 70 diff mean(x) Ha: diff < 0 Pr(Tt) = 0.9845 Mean 8.5 6.85 7.745714 C n 38 32 mean(y) .567775 B mean 8.5 6.85 Std. Err. Std. Dev. [95% Conf. Intervall 3834311 D S 3.5 2.6 3.5 2.6 3.208015 Ha: diff != 0 Pr(|T| > |t|) = F 7.349579 5.9126 6.98079 .1552544 degrees of freedom = 9.650421 7.7874 8.510638 3.144746 t = E 68 Ha: diff> 0 Pr(Tt) = 0.0155 b. What is the conclusion of your test? c. Use this output to construct a 99% confidence interval for the difference between the two means.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![.
3. A researcher is interested in knowing if preterm infants with late metabolic
acidosis and preterm infants without the condition differ with respect to urine
levels of a certain chemical. The mean levels, standard deviations, and sample
sizes from the two samples are given below. Assuming that the populations have
equal variances:
a. Fill in the missing pieces of the Stata output.
ttesti 38 8.5 3.5 32 6.85 2.6
X
y
Two-sample t test with A variances
combined
diff
Obs
Ho: diff=0
38
32
Sample
With condition
70
diff mean(x)
n
38
Without condition 32
Ha: diff < 0
Pr(Tt) = 0.9845
Mean
8.5
6.85
7.745714
C
mean (y)
mean
8.5
6.85
.567775
B
Std. Err. Std. Dev.
.3834311
S
3.5
2.6
3.5
2.6
3.208015
Ha: diff != 0
Pr(|T| > |t|) = F
[95% Conf. Intervall
7.349579
5.9126
6.98079
.1552544
t =
degrees of freedom =
9.650421
7.7874
8.510638
3.144746
E
b. What is the conclusion of your test?
c. Use this output to construct a 99% confidence interval for the difference
between the two means.
68
Ha: diff0
Pr(Tt) = 0.0155](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcfd420c3-c431-4bea-be72-f009b8b62993%2Fdeae55bf-1f10-4428-b1a1-32b6591802a0%2Fufhbaai_processed.png&w=3840&q=75)
Transcribed Image Text:.
3. A researcher is interested in knowing if preterm infants with late metabolic
acidosis and preterm infants without the condition differ with respect to urine
levels of a certain chemical. The mean levels, standard deviations, and sample
sizes from the two samples are given below. Assuming that the populations have
equal variances:
a. Fill in the missing pieces of the Stata output.
ttesti 38 8.5 3.5 32 6.85 2.6
X
y
Two-sample t test with A variances
combined
diff
Obs
Ho: diff=0
38
32
Sample
With condition
70
diff mean(x)
n
38
Without condition 32
Ha: diff < 0
Pr(Tt) = 0.9845
Mean
8.5
6.85
7.745714
C
mean (y)
mean
8.5
6.85
.567775
B
Std. Err. Std. Dev.
.3834311
S
3.5
2.6
3.5
2.6
3.208015
Ha: diff != 0
Pr(|T| > |t|) = F
[95% Conf. Intervall
7.349579
5.9126
6.98079
.1552544
t =
degrees of freedom =
9.650421
7.7874
8.510638
3.144746
E
b. What is the conclusion of your test?
c. Use this output to construct a 99% confidence interval for the difference
between the two means.
68
Ha: diff0
Pr(Tt) = 0.0155
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