3. A professor was curious about her students' grade point averages (GPAS). She took a randomsample of 15 students and found a mean GPA of 3.01 with a standard deviation of 0.534.a.For the given situation, identify the degrees of freedom and associated t-score for a 99%confidence interval.b. Using your answers from part (a), identify the margin of error for the given interval.c. Use your answer from part (c) to find the desired interval. Check your answer using the"Tinterval" computation on your calculator.

Given that, a professor was curious about her students' grade point averages (GPAS). She took a…

Answered: 3. A professor was curious about her…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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From the data plot provided please answer the following questions.
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Directions: 1. Answer the following items. 2. Find the appropriate sample size given the confidence level, standard deviation, and margin of error. 3. Round off to the nearest whole number. 4. Just write the number, no other symbols or variables, no spacing or comma. Problem: E = 0.36 kg, s = 20 kg, 95% confidence level
A medication is undergoing a clinical trial. They have taken the blood pressure of the participants on n=25 occasions. The mean blood pressure was 132 systolic for the participants with a standard deviation of 3 points. Construct a 90% and 95% confidence interval for the true mean systolic pressure. Interpret the confidence interval in your own words. Do you think this drug is effective based on the confidence interval? Why or why not?
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A professor was curious about her students' grade point averages. She took a random sample of 15 students and found a mean GPA of 3.01 with a standard deviation of 0.534. Which of the following formulas gives a 99% confidence interval for the mean GPA of the professor's students?
A survey of 32,782 adults in 2004 indicated that 24.6% of adults were current smokers. A similar study conducted in 1995 of 40,000 adults indicated that 29.7% were current smokers. a. Find and interpret a point estimate of the difference between the proportion of current smokers in 1995, and the proportion of current smokers in 2004. b. A 95% confidence interval for the true difference is (-0.058,-0.045). Interpret. c. What assumptions must you make for the confidence interval i part b to be valid? (…) a. Find a point estimate of the difference between the proportion of current smokers in 1995 and the proportion of current smokers in 2004. (Round to three decimal places as needed.)
Which type of confidence interval should you use in this situation? A sample of 25 different payroll departments found that the employees worked an average of 310.3 days a year with a standard deviation of 23.8 days. The distribution is approximately normally distributed. Find the 90% confidence interval for the average days worked of all payroll departments. Question 2 options: 1) a confidence interval for the mean using a table value from the standard normal distribution. 2) a confidence interval for the mean using a table value from the t distribution. 3) a confidence interval for a proportion using a table value from the standard normal distribution. 4) a confidence interval for proportion using a table value from the t distribution. 5) none of the above.
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
Christina wants to know the true average number of pages in a typical textbook. She randomly selects 196 books, and they have an average of 161 pages. Calculate a 90.3% confidence interval if you are given that the standard deviation for a single book is 75 pages.

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