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3. A closed flask contains gas at STP. If the temperature is raised to 1092 K what will the pressure be in atmospheres? Table A Standard Temperature and Pressure Name Value Unit Sturwlanl Pe plere 0/1 Pt Standud Teuperatue 273K Step 1: Write out the equation Р. 101.3 kРа 1 dege Celas Step 2: Identify the variables T, given in the problem P P2 T T2 %3D → →→ →→→ → P, Step 3: Plug the variables into the equation and solve for x T, P1 P2 T1 T2 FINAL ANSWER: 2.

3. A closed flask contains gas at STP. If the temperature is raised to 1092 K what will the pressure be in atmospheres? Table A Standard Temperature and Pressure Name Value Unit Sturwlanl Pe plere 0/1 Pt Standud Teuperatue 273K Step 1: Write out the equation Р. 101.3 kРа 1 dege Celas Step 2: Identify the variables T, given in the problem P P2 T T2 %3D → →→ →→→ → P, Step 3: Plug the variables into the equation and solve for x T, P1 P2 T1 T2 FINAL ANSWER: 2.

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A closed flask contains gas as STP. If the tempature is raised to 1092 K what will the pressure be in the atmospheres? (Identify the variables given)

3. A closed flask contains gas at STP. If the temperature is raised to 1092 K what will the pressure be in atmospheres? Table A Standard Temperature and Pressure Name Value Unit I1.3 ku kelepusenl ansphere kelvia degee Celstus Starlanl Pressre I atn 0/1 Pt Stuodsad Temperatue 273 K Step 1: Write out the equation P, 101.3 kPa Step 2: Identify the variables T, given in the problem P P2 T T2 →→→ →→→ → P2 Step 3: Plug the variables into the equation and solve for x T2 P2 T T2 P1 FINAL ANSWER:
Transcribed Image Text:3. A closed flask contains gas at STP. If the temperature is raised to 1092 K what will the pressure be in atmospheres? Table A Standard Temperature and Pressure Name Value Unit I1.3 ku kelepusenl ansphere kelvia degee Celstus Starlanl Pressre I atn 0/1 Pt Stuodsad Temperatue 273 K Step 1: Write out the equation P, 101.3 kPa Step 2: Identify the variables T, given in the problem P P2 T T2 →→→ →→→ → P2 Step 3: Plug the variables into the equation and solve for x T2 P2 T T2 P1 FINAL ANSWER:
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