3. A 4.912-g sample of a petroleum product was burned in a tube furnace, and the SO₂ produced was collected in 3% H₂O2. Reaction: SO2(g) + H₂O2 → H₂SO4. A 25.00-mL portion of 0.00873 M NaOH was introduced into the solution of H₂SO4, following which the excess base was back-titrated with 15.17 mL of 0.01102 M HCI. Calculate the sulfur concentration in the sample in parts per million.

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3. A 4.912-g sample of a petroleum product was burned in a tube furnace, and the SO2
produced was collected in 3% H₂O₂. Reaction: SO2(g) + H₂O2 → H₂SO4. A 25.00-mL portion
of 0.00873 M NaOH was introduced into the solution of H₂SO4, following which the
excess base was back-titrated with 15.17 mL of 0.01102 M HCI. Calculate the sulfur
concentration in the sample in parts per million.
Transcribed Image Text:3. A 4.912-g sample of a petroleum product was burned in a tube furnace, and the SO2 produced was collected in 3% H₂O₂. Reaction: SO2(g) + H₂O2 → H₂SO4. A 25.00-mL portion of 0.00873 M NaOH was introduced into the solution of H₂SO4, following which the excess base was back-titrated with 15.17 mL of 0.01102 M HCI. Calculate the sulfur concentration in the sample in parts per million.
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