Twenty tablets of an iron food supplement whose total mass was 22.131 g were crushed and perfectly mixed. Then 2.998g of the powder was dissolved in HNO3 and the solution was heated to convert all the iron to Fe+3. By addition of NH3 it was quantitatively precipitated as Fe(OH)3 H2O which was calcined to form 0.264g of Fe203. Calculate the Fe content in each tablet.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Twenty tablets of an iron food
supplement whose total mass was
22.131 g were crushed and perfectly
mixed. Then 2.998g of the powder
was dissolved in HNO3 and the
solution was heated to convert all the
iron to Fe+3. By addition of NH3 it
was quantitatively precipitated as
Fe(OH)3•H20 which was calcined to
form 0.264g of Fe203. Calculate the
Fe content in each tablet.
Transcribed Image Text:Twenty tablets of an iron food supplement whose total mass was 22.131 g were crushed and perfectly mixed. Then 2.998g of the powder was dissolved in HNO3 and the solution was heated to convert all the iron to Fe+3. By addition of NH3 it was quantitatively precipitated as Fe(OH)3•H20 which was calcined to form 0.264g of Fe203. Calculate the Fe content in each tablet.
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