A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs out 459. mg of oxalic acid (H,C,0), a diprotic acid that can be purchased inexpensively in high purity, and dissolves it in 250. mL of distilled water. The student then titrates the oxalic acid solution with his sodium hydroxide solution. When the titration reaches the equivalence point, the student finds he has used 121.4 mL of sodium hydroxide solution. Calculate the molarity of the student's sodium hydroxide solution. Be sure your answer has the correct number of significant digits.

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A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs out 459. mg of oxalic acid (H,C,O), a diprotic acid that
can be purchased inexpensively in high purity, and dissolves it in 250. mL of distilled water. The student then titrates the oxalic acid solution with his sodium
hydroxide solution. When the titration reaches the equivalence point, the student finds he has used 121.4 mL of sodium hydroxide solution.
Calculate the molarity of the student's sodium hydroxide solution. Be sure your answer has the correct number of significant digits.
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Transcribed Image Text:A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs out 459. mg of oxalic acid (H,C,O), a diprotic acid that can be purchased inexpensively in high purity, and dissolves it in 250. mL of distilled water. The student then titrates the oxalic acid solution with his sodium hydroxide solution. When the titration reaches the equivalence point, the student finds he has used 121.4 mL of sodium hydroxide solution. Calculate the molarity of the student's sodium hydroxide solution. Be sure your answer has the correct number of significant digits. FEB 19 MacBook Air DII DD 80 888 F7 F3 & $ の
Expert Solution
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It is acid-base titration. We knew that sodium hydroxide is not the primary standard solution. So we need to be standardized first. So we use oxalic acid. At the equivalence point, moles of acid neutralized the mole of the base completely. 

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