3. (2 points) A small negatively-charged plastic ball with mass of m = 2.0 g and charge of Q = -0.3 C is floating in the air without falling to the floor because of an electric field that exerts a force on the ball. Find the magnitude and direction of the electric field.
3. (2 points) A small negatively-charged plastic ball with mass of m = 2.0 g and charge of Q = -0.3 C is floating in the air without falling to the floor because of an electric field that exerts a force on the ball. Find the magnitude and direction of the electric field.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:Magnitude :
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3. (2 points) A small negatively-charged plastic ball with mass of m = 2.0 g and charge of
Q = -0.3 C is floating in the air without falling to the floor because of an electric field that
exerts a force on the ball. Find the magnitude and direction of the electric field.
magntuide
direction
1
4. (2 points) Two charges are aligned vertically where Q1 = +4C and Q2 = -2C. The
distance between Q and Qo is a Two regions are labelled as 4 and R rognoativolu in tho
%3D
rosnogtivoly in the
Expert Solution
Step 1
The magnitude of electrostatic force due to an electric field is given by
where,
F - Force
E - Electric field
q - Charge
The gravitational force is
where,
m - mass of the charge
g - acceleration due to gravity
For two balancing forces, the direction of one force will be opposite to the other force.
The electric field can be found by equating the gravitational force and the electrostatic force
Given data
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