3 Write the expression for the equilibrium constant Kp for the following reaction. Enclose pressures in parenthèses and do NOT write the chemical formula as a subscript. For example, enter (PNH3)² as (P NH3)². If either the numerator or denominator is 1, please enter 1 [Review Topics] [References] Use the References to access important values if needed for this question. NOV 30 An error has been detected in your answer. Check for typos, miscalculations etc. before submitting your answer. Q 2 Mn304(s) → 6 MnO(s) + O₂(g) Submit Answer F4 K = Retry Entire Group 9 more group attempts remaining #tv ♫ 0 F5 MacBook Air C F6 8₁ 8 F7 * A F8 Previous Email Instructor F9 O Next> Save and Exit J F10 Dov

3 Write the expression for the equilibrium constant Kp for the following reaction. Enclose pressures in parenthèses and do NOT write the chemical formula as a subscript. For example, enter (PNH3)² as (P NH3)². If either the numerator or denominator is 1, please enter 1 [Review Topics] [References] Use the References to access important values if needed for this question. NOV 30 An error has been detected in your answer. Check for typos, miscalculations etc. before submitting your answer. Q 2 Mn304(s) → 6 MnO(s) + O₂(g) Submit Answer F4 K = Retry Entire Group 9 more group attempts remaining #tv ♫ 0 F5 MacBook Air C F6 8₁ 8 F7 * A F8 Previous Email Instructor F9 O Next> Save and Exit J F10 Dov

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For this reaction: 2CO2(g) 2CO(2) + O2(e) Kequals 2.35 x 10Pat a particular temperature. If 3.5 moles of CO2 are initially placed into a 3.0L flask, calculate the equilibrium concentrations of all species. YOU MUST SHOW ALL OF YOUR WORK. | Drag n' Drop here or Browse Next
Construct the expression for Kp for the following reaction. C(s) + 2 Cl₂(g) = CCI(g) Drag the tiles into the numerator or denominator to form the expression. Each reaction participant must be represented by one tile. Do not combine terms. Pccl (PC₁₂)² 2(PCC) Кр (Pcci,)² 1 Pc 2(Pc) (Pc)² Pcl₂ RESET 2(PC₁₂)
Construct the expression for Kp for the following reaction. CC:(g) = C(s) + 2 Cl:(g) 1 Drag the tiles into the numerator or denominator to form the expression. Each reaction participant must be represented by one tile. Do not combine terms. Kp 5 RESET PC. 2(PCcı) (PCcL)? Pc 2(Pc) (Pc)? PCL 2(Рсь) (PCL)?
Just do questions no.18 in 20 minutes
Consider the synthesis of hydrogen iodide from molecular hydrogen and iodide. At equilibrium a ressel contains a mixture of I2 (purple), H₂ Colorless) and HI (colorless). The value of Kc=56 at 200k. H₂(g) + Iz(g)=ZHI(g) e) IH Now ( 30 a) If the purple color of the mixture fades as the temperature is raised is the reaction forming FI exothermic or endothermic? llow SI to tavom IN SI to- AD 91 23 19225v silt to Sulov NASAW b) A flask is immersed in a constant-temp. bath maintained @ 200 kelvin. The flask initially contains: [H₂] = 0.024M, [1₂]=0.036M [HI] = 0.15 M. Will the [HI] increase or decrease? c) C) (E hat is 632 show now owa ni the value of kc for this ran bild HI(g) = 1/2 H₂(g) + 1/2 12 (9) 01. 11
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Equilibrium pressure calculation
20 A student ran the following reaction in the laboratory at 330 K: [Review Topics] [References] Use the References to access important values if needed for CH4 (9) + CCl4 (g) = 2CH₂Cl₂ (g) When she introduced 0.0438 moles of CH4 (g) and 0.0602 moles of CCL4 (g) into a 1.00 liter container, she found the equilibrium concentration of CCl4 (g) to be 0.0544 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = Submit Answer Retry Entire Group 9 more group attempts remaining Show Hint Cengage Learning | Cengage Technical Support MacBook Air
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NetID: Name: 8. What is [NO] and [CO₂] (in M to two decimal places) at equilibrium for the following reaction at 227 °C if the initial concentrations of each reactant is 1.25 M? Explain the validity of your final answer using chemical intuition. NO₂(g) + CO(g) = NO(g) + CO₂(8) -224.09 kJ mol-1 K(227 °C) = 6.9x105 A: [NO] = 1.25; [CO₂] = 1.25