Use the References to access important values if needed for this question. Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is: AIBR3(s)! Al(s) + 3/2 Br2(1) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) 2 AIBR3(s) 2 2 Al(s) + 3 Br2(1) K1 = 2) Al(s) + 3/2 Br21) 2 AIBR3(s) K2 = 3) 2 Al(s) +3 Br21) 2 2 AIBR3(s) K3 = Drag and drop your selection from the following list to complete the answer: K? 1/K (1/K)?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Use the References to access important values if needed for this question.
Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder).
One way to represent this equilibrium is:
AIBR3(s)L
Al(s) + 3/2 Br2(1)
We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of
K, the equilibrium constant for the reaction above.
1) 2 AIBr3(s)
? 2 Al(s) + 3 Br21)
K1 =
2) Al(s) + 3/2 Br21) 2 AIB13(s)
K2 =
3) 2 Al(s) +3 Br2(1) 2 2 AIB13(s)
K3 =
Drag and drop your selection from the following list to complete the answer:
K?
1/K
(1/K)?
Submit Answer
Retry Entire Group
No more group attempts remain
Transcribed Image Text:Use the References to access important values if needed for this question. Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is: AIBR3(s)L Al(s) + 3/2 Br2(1) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) 2 AIBr3(s) ? 2 Al(s) + 3 Br21) K1 = 2) Al(s) + 3/2 Br21) 2 AIB13(s) K2 = 3) 2 Al(s) +3 Br2(1) 2 2 AIB13(s) K3 = Drag and drop your selection from the following list to complete the answer: K? 1/K (1/K)? Submit Answer Retry Entire Group No more group attempts remain
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