3- Reaction between barium chloride and sulfuric acid: A volume V= 100 ml of solution S1 with concentration C= 2× 10-3 molL is added to 0.002 mol of sulfuric acid H2SO4, barium sulfate is formed according to the following equation: BaCl2(aq) + H,SO(aq) → 2 HCl (aq) + BaSO4) Given: M (BaS04) = 233 g.mol- 3.1- Specify the limiting reagent. 3.2- Determine the amount (in mol) of excess reactant that remained at the end of reaction. 3.3- Calculate the mass of BaSO4 that should be obtained at the end of the reaction. 3.4-Determine the yield of this reaction if 0.022g of barium sulfate is obtained.
3- Reaction between barium chloride and sulfuric acid: A volume V= 100 ml of solution S1 with concentration C= 2× 10-3 molL is added to 0.002 mol of sulfuric acid H2SO4, barium sulfate is formed according to the following equation: BaCl2(aq) + H,SO(aq) → 2 HCl (aq) + BaSO4) Given: M (BaS04) = 233 g.mol- 3.1- Specify the limiting reagent. 3.2- Determine the amount (in mol) of excess reactant that remained at the end of reaction. 3.3- Calculate the mass of BaSO4 that should be obtained at the end of the reaction. 3.4-Determine the yield of this reaction if 0.022g of barium sulfate is obtained.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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