+ Jumper Cables and Ohm's Law3 of 20I Review | ConstantsLearning Goal:To learn to apply the concept of current densityand microscopic Ohm's law.Part DA "gauge 8" jumper cable has a diameter d of0.326 cm. The cable carries a current I of 30.0A. The electric field E in the cable is 0.062V/m.The resistance R of a copper "gauge 10" jumper cable with diameter d = 0.259 cm is 0.0124 2. Find the lengthL of the cable.Express your answer in m. Use three significant figures.Below is a list of some common metals withtheir resistivities.• View Available Hint(s)Resistivitye (N. m)Materialανα ΑΣφ?copper1.72 x 10-8L =msilver1.47 x 10-8aluminum 2.75 x 10-8Submitgold2.44 x 10-8Provide FeedbackNext>steel20 × 10-8

Answered: Image /qna-images/answer/5ae41660-fb62-4fd1-a627-0d1a22ca2fb4.jpg

Answered: 3 of 20 Review | Constants Learning…

Similar questions

Part A A length of aluminum wire is connected to a precision 10.00-V power supply, and a current of 0.4192 A is precisely measured at 23.5 °C. The wire is placed in a new environment of unknown temperature where the measured current is 0.3698 A . The temperature coefficient of resistivity of aluminum is 0.00429 (°C)-1 What is the unknown temperature? Express your answer using three significant figures. να ΑΣφ ? T = °C Submit Request Answer Provide Feedback
need help with following
A long, cylindrical wire with a length of 1.5 m and a cross-sectional area of 5.0 mm2 carries a steady current of 5.0 A. If the number density of free electron carriers in the wire is 8.0 x 1028 e- ' s/m3, what is the drift velocity of the free electrons that carry the current? a. 6.5 x 10-7 m/s b. 7.8 x 10-7 m/s c. 4.2 x 10-7 m/s d. 9.7 x 10-7 m/s e. 2.1 x 10-6 m/s
Part A A 8.8×10-4 V/m electric field creates a 4.9x1017 electrons/s current in a 1.8-mm-diameter aluminum wire. What is the drift speed? Express your answer using two significant figures. "να ΑΣφ ? va = m/s Submit Request Answer Part B What is the mean time between collisions for electrons in this wire? Express your answer using two significant figures. T = Submit Request Answer
hiii I need help with part a and part b
Part A A 5.1x10 V/m electric field creates a 3.5x1017 electrons/s current in a 2.0-mm-diameter aluminum wire. What is the drift speed? Express your answer using two significant figures. m/s = Pa Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B What is the mean time between collisions for electrons in this wire? Express your answer using two significant figures.
F2 An aluminum wire 1.628 mm in diameter (14-gauge) carries a current of 5 amps. Overall Hint a. What is the number density of charge carriers (electrons) in the wire? # 3 3 Hint for (a) 1 The number density of electrons in the wire is m³ (Use "E" notation to enter your answer in scientific notation. For example, to enter 3.14 × 10¹2, enter "3.14E12".) b. What is the magnitude of the drift velocity of the electrons? Hint for (b) The drift velocity of the electrons is vd = c. What would be the drift velocity if the same gauge copper were used instead of aluminum? Hint for (c) For the same gauge copper wire, the drift velocity would be va r Question Help: Message instructor Submit Question There is a disconnect between how small drift velocities are and how quickly electrical signals travel through wires (nearly at the speed of light). For the moment, treat the two as completely unrelated to each other. 80 F3 54 $ 4 F4 C do 5 % F5 ㅏ < 6 6 MacBook Air F6 = & 7 8 AA m/s. F7 * 8 m/s. DII F8…
Two 9.0-cm-diameter metal plates 1.2 cm apart are charged to +12.5 nC. They are suddenly connected together by a 0.218-mm-diameter copper wire stretched taut from the center of one plate to the center of the other. Part A What is the maximum current in the wire? Express your answer with the appropriate units. ► View Available Hint(s) Imax = 2.67 10³ A ?
q2
QUESTION 7 A copper wire has a circular cross section with a diameter of 8.11 mm. If the wire carries a current of 1.45 A, find the drift speed (in m/s) of electrons in the wire. (Take the density of mobile charge carriers in copper to be n = 1.10 × 1029 electrons/m³ and charge of electron to be q = 1.61 × 10-19 X C). Area of a circle = pir^2 Submit your answer in exponential form with two decimal places. You are required to show your work in the file you submit.