I ReviewFor safety reasons, electrical codes have beenestablished that limit the amount of current a wire ofa given size can carry. For example, an 18-gauge(cross-sectional area = 1.17 mm? ), rubber-insulated extension cord with copper wires cancarry a maximum current of 5.0 A.Part AFind the voltage drop in a 14 – ft , 18-gauge extensioncord carrying a current of 5.0 A. (Note: In an extensioncord, the current must flow through two lengths-down andback.)Express your answer using two significant figures.ΑΦVV> ||

Answered: Review For safety reasons, electrical…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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I Review
For safety reasons, electrical codes have been
established that limit the amount of current a wire of
a given size can carry. For example, an 18-gauge
(cross-sectional area = 1.17 mm? ), rubber-
insulated extension cord with copper wires can
carry a maximum current of 5.0 A.
Part A
Find the voltage drop in a 14 – ft , 18-gauge extension
cord carrying a current of 5.0 A. (Note: In an extension
cord, the current must flow through two lengths-down and
back.)
Express your answer using two significant figures.
ΑΦ
V
V
> ||

Expert Solution

Step 1

$maximum current (i) = 5 A Cross sectional area of wire (A) = 1.17 m m^{2} U \sin g, 1 m = 1000 m m A = 1.17 \times 10^{- 6} m^{2} Length of wire = 14 f t u \sin g, 1 f t = 0.3048 m = 4.267 m Total length of wire in extension cord = 2 \times 4.267 = 8.534 m Resistivity of copper = 1.72 \times 10^{- 8} o h m . m e t e r$

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