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3 Induction Coil Solenoid A closed copper coil with 100 turns of wire and a total resistance of R = 5.00 is placed outside of a solenc • The radius of the coil is a = 2.0 cm. 0.000

3 Induction Coil Solenoid A closed copper coil with 100 turns of wire and a total resistance of R = 5.00 is placed outside of a solenc • The radius of the coil is a = 2.0 cm. 0.000

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3 Induction Coil Solenoid A closed copper coil with 100 turns of wire and a total resistance of R = 5.00 is placed outside of a solenoid. • The radius of the coil is a = 2.0 cm. • The solenoid is 10 cm long and has 2,000 turns of wire. Its radius is a = 1.5 cm. • The solenoid is connected to a power supply and the current increases steadily from 0 to 2.0 A in 50 ms. What current is induced in the copper coil?
Transcribed Image Text:3 Induction Coil Solenoid A closed copper coil with 100 turns of wire and a total resistance of R = 5.00 is placed outside of a solenoid. • The radius of the coil is a = 2.0 cm. • The solenoid is 10 cm long and has 2,000 turns of wire. Its radius is a = 1.5 cm. • The solenoid is connected to a power supply and the current increases steadily from 0 to 2.0 A in 50 ms. What current is induced in the copper coil?
Expert Solution
Step 1

Given Data

  • The number of turns of copper coil is:N=100 turns
  • The total resistance is:R=5Ω
  • The radius of the coil is:a=2 cm=2×10-2 m
  • The length of solenoid is:L=10 cm=0.1m
  • The number of turns of solenoid is:n=2000 turns
  • The radius of solenoid is:a=1.5 cm=0.015 m
  • The change in current is:∆I=2 A
  • The change in time is∆t=50ms=50×10-3 s

To find:

The current is induced in the copper coil,

Formula used:

The magnetic field due to solenoid is given as,

B=μonI

Here,

B is the magnetic field

μo is the magnetic permiability

n is the number of turns of solenoid.

I is the current

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