-3 In a conductor, if the number of conduction electrons per unit volume is 8.5x1028 m and mean free time is 25 fs (femto second), it's approximate resistivity is (Take, m. = 9.1×10-³1 kg) (3) 10 Ω-m (c) 102-m (b) 10-52-m (d) 10-822-m
-3 In a conductor, if the number of conduction electrons per unit volume is 8.5x1028 m and mean free time is 25 fs (femto second), it's approximate resistivity is (Take, m. = 9.1×10-³1 kg) (3) 10 Ω-m (c) 102-m (b) 10-52-m (d) 10-822-m
Related questions
Question
![In a conductor, if the number of conduction electrons per unit
volume is 8.5×10²8 and mean free time is 25 fs (femto
-3
m
second), it's approximate resistivity is
9.1×10-³1 kg)
(Take, m₂ = 9.1 x 107
me
(a) 10 Q-m
(c) 10¯n-m
(b) 10¯5 №-m
(d) 108 №-m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a34367b-b570-41cb-a05e-cf3382afeb7f%2Fa7275278-9e50-49b9-8b4a-02f2528001c6%2Fppjpl2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In a conductor, if the number of conduction electrons per unit
volume is 8.5×10²8 and mean free time is 25 fs (femto
-3
m
second), it's approximate resistivity is
9.1×10-³1 kg)
(Take, m₂ = 9.1 x 107
me
(a) 10 Q-m
(c) 10¯n-m
(b) 10¯5 №-m
(d) 108 №-m
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)