3- Derive the rule-of-mixtures equation (a₂ = a{Vf + amVm) for the coefficient of thermal expansion α2. Compare the variation of a₂ based on rule-of-mixtures & alternative rule with fiber volume fraction for graphite-reinforced material (use numerical values of question 1 for fiber and matrix properties).

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Inputs:
Outputs:
●
●
●
=
E₁, E2, U12, G₁2, α₁ and a₂
Use the following numerical values for sample calculation: (vf
●
E{ = 233 GPa
v2 = 13 = 0.200
Fiber properties
Matrix properties
Fiber volume fraction
G2 G3 = 8.96 GPa
a = -0.540 x 10-6/K
E = E= 23.1 GPa
23 = 0.400
G₁3
α₂ = α² = 10.10 x 10-6/K
= 8.27 GPa
=
0.6)
Em
4.62 GPa
a = 41.4 x 10-6/K
= 0.360
Transcribed Image Text:Inputs: Outputs: ● ● ● = E₁, E2, U12, G₁2, α₁ and a₂ Use the following numerical values for sample calculation: (vf ● E{ = 233 GPa v2 = 13 = 0.200 Fiber properties Matrix properties Fiber volume fraction G2 G3 = 8.96 GPa a = -0.540 x 10-6/K E = E= 23.1 GPa 23 = 0.400 G₁3 α₂ = α² = 10.10 x 10-6/K = 8.27 GPa = 0.6) Em 4.62 GPa a = 41.4 x 10-6/K = 0.360
3- Derive the rule-of-mixtures equation (α₂ = α{V¹ + a²Vm) for the coefficient of thermal expansion α₂.
Compare the variation of a₂ based on rule-of-mixtures & alternative rule with fiber volume fraction for
graphite-reinforced material (use numerical values of question 1 for fiber and matrix properties).
Transcribed Image Text:3- Derive the rule-of-mixtures equation (α₂ = α{V¹ + a²Vm) for the coefficient of thermal expansion α₂. Compare the variation of a₂ based on rule-of-mixtures & alternative rule with fiber volume fraction for graphite-reinforced material (use numerical values of question 1 for fiber and matrix properties).
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