7by taking n= 6| In x- dx solution of the integral with Simpson's3method813. (y, + y, + y, + Y; +...p-2)? O A) 16.579B) 15.579O C) 13.579O D) 14.579O E) 12.579

Answered: Image /qna-images/answer/5ca0c0bb-321d-4913-8724-4549b572f097.jpg

Answered: 3 by taking n= 6 [In x · dx solution of…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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a=4 b=4 c=5
X^2 sin(2y Sz)=1+ycos(6zx) fo2/ D [4xsin(2y-5z)-sin(ósx)6zy /os(2y-Sz)(-5)x2- sin(zx]6xy]| [2xsin(2y-5zltsin(6zx]ozcos(2y-Sz)(-5)xsin(6zx]6xy| D. [2xsin(2y-52)-sin(3zx)6zy/lcos(2y-52)(-5)x2sin(6zx)6xz|
Evaluate the following: (Show clear and clean solutions) A. By simple integration rules 1. fki+3x-2 + 5x+)dx 2. S x3 -5x²+4x dx (x-1) 3. S**-343 dx х-7 4. S Vx² – 10x + 25 dx B. By Simple Substitution 1. S(x³ – 5)° x²dx х-6 2. S dx х2—36 3. S(4e2x – 1)5e2x dx - cos2x 4. S (1-sin2x)4 C. Evaluate the definite integrals ( show your solutions) 1. (x³ – 6x² + 2x)dx 2. 3 cos3 3xsin3xdx
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In x +1 If y = 2x3 – 3x' dy then will be dx (2x3 – 3x) G+ 1) – (2x³ – 3x)² (In x + 1)(6x² – 3) A. (2x³ – 3x) Inx – (In x + 1)(6x? – 3) В. (2x3 – 3x)? (2x – 3x) -1) – (In x + 1)(6x? + 3) (2x³ – 3x)² C. (2х? — 3) — (Inx + 1)(6х? — 3) D. (2x³ – 3x)² Select one: ов O C O A
2 (1+x)²dx=1+y² dy 6 x cosy dx - siny = 0 | 7 7 (x³ + xy²) dy=2y³ dx dy 12 Xdx +3y=x²y² 8 (x² − 1) dx + 2xy = x dy
Is it possible to solve two points or all points in a maximum time of 20 minutes
The general solution to the DE, (x^2+y^2-5)dx = (y+xy)dy, is * -0.5y^2/((x+1)^2) + 2/(x+1) + 2/((x+1)^2) + 21n(x+1) = c -0.5y^2/((x+1)^2) + 2/((x+1)^2) + 2ln(x+1) = c %3D -0.5y^2/((x+1)^2) + In(x+1) +2/(x+1) + 2/((x+1)^2) = c -0.5y^2/((x+1)^2) + 2/((x+1)^2) + 2ln(x+1)+ 1/(x+1) = c
10:58 X PROBLEMSET_FI... TRIGO SUBSTITUTION Evaluate the following integrals. dx 1. S (a²+x²)z dx x√x²-a² 3. √ √a² + x²dx 4. √ √a²-x²dx 5. √ √x²-a²dx 6. √4-25x²dx 7. S 8. S 2. S= 9. 10.S 4x²-81 dx 5y dy (x²+25)3 √9-(x + 3)² dx w²dw (4+16w²)z 11. x² dx 9-4x² 12.fdx .LTE 39 x(x²-9)Z 13. √ √4-x² dx S

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3 by taking n= 6 [In x · dx solution of the integral with Simpson's • method 3. (y, + y2 + y4 + y3 + ...Yp-2) |00