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The general solution to the DE, (x^2+y^2-5)dx = (y+xy)dy, is * -0.5y^2/((x+1)^2) + 2/(x+1) + 2/((x+1)^2) + 2ln(x+1) = c -0.5y^2/((x+1)^2) + 2/((x+1)^2) + 2ln(x+1) = c -0.5y^2/((x+1)^2) + In(x+1) +2/(x+1) + 2/((x+1)^2) = c -0.5y^2/((x+1)^2) + 2/((x+1)^2) + 2ln(x+1)+ 1/(x+1) = c

The general solution to the DE, (x^2+y^2-5)dx = (y+xy)dy, is * -0.5y^2/((x+1)^2) + 2/(x+1) + 2/((x+1)^2) + 2ln(x+1) = c -0.5y^2/((x+1)^2) + 2/((x+1)^2) + 2ln(x+1) = c -0.5y^2/((x+1)^2) + In(x+1) +2/(x+1) + 2/((x+1)^2) = c -0.5y^2/((x+1)^2) + 2/((x+1)^2) + 2ln(x+1)+ 1/(x+1) = c

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The general solution to the DE, (x^2+y^2-5)dx = (y+xy)dy, is * -0.5y^2/((x+1)^2) + 2/(x+1) + 2/((x+1)^2) + 21n(x+1) = c -0.5y^2/((x+1)^2) + 2/((x+1)^2) + 2ln(x+1) = c %3D -0.5y^2/((x+1)^2) + In(x+1) +2/(x+1) + 2/((x+1)^2) = c -0.5y^2/((x+1)^2) + 2/((x+1)^2) + 2ln(x+1)+ 1/(x+1) = c
Transcribed Image Text:The general solution to the DE, (x^2+y^2-5)dx = (y+xy)dy, is * -0.5y^2/((x+1)^2) + 2/(x+1) + 2/((x+1)^2) + 21n(x+1) = c -0.5y^2/((x+1)^2) + 2/((x+1)^2) + 2ln(x+1) = c %3D -0.5y^2/((x+1)^2) + In(x+1) +2/(x+1) + 2/((x+1)^2) = c -0.5y^2/((x+1)^2) + 2/((x+1)^2) + 2ln(x+1)+ 1/(x+1) = c
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