3) Based on the value for [H3O*], calculate the pH of this 0.160 M HPro solution. 4) Calculate the value for [OH¯] of this 0.160 M HPro solution.
3) Based on the value for [H3O*], calculate the pH of this 0.160 M HPro solution. 4) Calculate the value for [OH¯] of this 0.160 M HPro solution.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please solve question 3 and 4 only (they are very closely interconnected). Thank you!
![Propanoic acid is a weak monoprotic acid with the formula HC3H5O2. It partially dissociates in
water to release hydronium ions (H3O*) and propanoate ions (C;H5O2-). We can abbreviate
propanoic acid as “HPro" and the propanoate ion as Prol-. The acid-dissociation equilibrium for
propanoic acid is described below.
HPro (aq) + H2O () = H3O*(aq) + Pro- (aq)
At 25°C, Ka, is 1.3 × 10-5
1)
Write the mass-action expression for this reaction. (As a pure liquid, H2O is not included).
The K value for this reaction is equal to Ka.
2)
Use an "ICE" (or "IAE" table to determine the concentrations of HPro, H3O†, and Prol- in an
aqueous solution of 0.160 M HPro.
3)
Based on the value for [H3O*], calculate the pH of this 0.160 M HPro solution.
4) Calculate the value for [OH¯] of this 0.160 M HPro solution.
5) The percent dissociation of a weak acid depends on the initial concentration of HA ([HA]o).
It is found using this value and the equilibrium concentration of {H*] ([H*]e).
([H*]e`
|(100%)
THAJO.
[HA],
% dissociation
Calculate the percent dissociation of 0.160 M HPro.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F476b5cb0-a3fb-4b49-8c26-098fb10da8e5%2Fead1f113-3394-4b00-a251-67a12fc4ec20%2Fmehoxyn_processed.png&w=3840&q=75)
Transcribed Image Text:Propanoic acid is a weak monoprotic acid with the formula HC3H5O2. It partially dissociates in
water to release hydronium ions (H3O*) and propanoate ions (C;H5O2-). We can abbreviate
propanoic acid as “HPro" and the propanoate ion as Prol-. The acid-dissociation equilibrium for
propanoic acid is described below.
HPro (aq) + H2O () = H3O*(aq) + Pro- (aq)
At 25°C, Ka, is 1.3 × 10-5
1)
Write the mass-action expression for this reaction. (As a pure liquid, H2O is not included).
The K value for this reaction is equal to Ka.
2)
Use an "ICE" (or "IAE" table to determine the concentrations of HPro, H3O†, and Prol- in an
aqueous solution of 0.160 M HPro.
3)
Based on the value for [H3O*], calculate the pH of this 0.160 M HPro solution.
4) Calculate the value for [OH¯] of this 0.160 M HPro solution.
5) The percent dissociation of a weak acid depends on the initial concentration of HA ([HA]o).
It is found using this value and the equilibrium concentration of {H*] ([H*]e).
([H*]e`
|(100%)
THAJO.
[HA],
% dissociation
Calculate the percent dissociation of 0.160 M HPro.
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