3 B. Construct two models of lactic acid. CH3-CH-C=0 C-2 is a chiral carbon atom. ОН ОН он Test to see if the two models are superimposable. If they are superimposable exchange the H and OH groups on C-2, which will make them non-superimposable. Once again the two non-superimposable isomers are enantiomers, and one com- pound will rotate plane-polarized light to the right and the other will rotate the light to the left.

3 B. Construct two models of lactic acid. CH3-CH-C=0 C-2 is a chiral carbon atom. ОН ОН он Test to see if the two models are superimposable. If they are superimposable exchange the H and OH groups on C-2, which will make them non-superimposable. Once again the two non-superimposable isomers are enantiomers, and one com- pound will rotate plane-polarized light to the right and the other will rotate the light to the left.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

e. Identify each chiral center (label *) and indicate R/S configuration O H2N H HO Но f. How is each compound related to the simple sugar D-erythrose? Is it an enantiomer, a diastereomer, or an identical molecule? OH HO OH D-erythrose OH HO OH но HO" 'HO, OH HO OH 3
There are 20 common, naturally occurring amino acids from which all proteins are derived (as will be discussed in Chapter 25), although many other less common amino acids have been isolated from natural sources. Valine is one of the 20 common amino acids, and it was used as a starting material in the laboratory synthesis of an uncommon amino acid (Tetrahedron 1997, 53, 1151-1156). During one of the steps in the synthesis, compound 1 was treated with HBr under conditions that favor radical addition, giving stereoisomers 2 and 3. Draw the structures of 2 and 3, and describe their stereoisomeric relationship. H3C- CH₂ H N HT H (S)-valine -CH3 00 Modify the given copies of compound 1 to drawthe structures of 2 and 3. You can use the single bond tool to add/remove double bonds. H3C- -N & N CH₂ HBr OCH₂ hv -CH3 2 + 3
OH OH Br Br OH JOH OH OH OH ado Br Br OH all letters that apply all letters that apply all letters that apply A enantiomers B diasteromers C different conformations of the same molecule D identical comformations of the same molecule E constitutional isomers F stereoisomers G different molecules H both are chiral I neither is chiral
Using the priority rule, identify the configuration at each chiral center and the configuration of the double bond: For a chiral center please type EXACTLY one of the following: R or S or neither if it is not a chiral center. For a double bond please type EXACTLY one of the following: E or Z or neither if the double bond has no stereochemistry.
23) Label the following pair as a/an enantiomer, diasteromer, structural isomer or identical C₂H5 НО (I) C₂H5 Н. (II) (III) HO НО OH -C2H5 он || -C2H5 OH НО Н. но. Н OH C₂H5 OH C₂H5 H H OH ОН
a. C1- C3- For each chiral carbon labeled in the structures below (see the numbers), assign R or S absolute configuration in the boxes provided - you only need to enter R or S. Then, state (in the box provided) whether the molecules are enantiomers, identical, diastereomers, or not related. 0 OH OH 2 OH X 3 and 1-44 C2- C4- OH and OH 2 Related- hp
As we have seen in monosaccharides can be drawn in avariety of ways, and in truth, often a mixture of cyclic compounds ispresent in a solution. Identify each monosaccharide, including its properD,L designation, drawn in a less-than-typical fashion.
124,528 X 8: 3 E D Enantiomers are a pair of molecules that are non-superimposable mirror images. Identify the two molecules that are a pair of enantiomers. Compound 1 OH 20 Compound 3 F3 OH $ OCT 3 R F TL C a F4 V % 5 OH Compound 2 T Compound 4 OH I F5 G tv B JONA FO Y H & 7 A N F7 U 8 J 33341 DII FB 1 M ( 9 K DD F9 W O H ) O A) Compounds 1 and 2 B) Compounds 1 and 3 C) Compounds 2 and 3 D) Compounds 1 and 4 E) Compounds 3 and 4 EA F10 L - P command F11 { +' [ F12 option
4. Identify the isomers below as structural, cis-trans, or enantiomers. 5.Is this molecule a ketose or aldose sugar?
1. For the structure below, assign the chiral centers with R/S configurations. Draw an enantiomer and diastereomer. Convert the original structure to Fischer Projection. OH HO NH₂
Two sugars differing in configuration at a single asymmetric carbon atom are known as epimers. D-mannose is a C-2 epimer of glucose (Structure I), while D-galactose is a C-4 epimer of glucose. Structure II and III are II: galactose, III: mannose II: mannose; III: galactose II and III are mannose II and III are galactose
Convert the following carbohydrate from a Chair Conformation to a Fischer Projection. МТg2МzМ4, 186338 ОН НО OH О OH OH Please hand draw and upload a photograph of your answer.