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3 Allele distributions in Generation 1: 36 homozygous dominant individuals 13 heterozygous individuals 1 homozygous recessive individual There are 50 individuals in this particular population. We want to see if allele distributions change from generation to generation. We will use the Hardy Weinberg equations to find out. Due to migration and random mating of the parent generation, the percentage of homozygous recessive genotypes in Generation 2 offspring increases, changing "a" to 40%, so a = .40 If "a" = .40, and "a" = q, then q = Remember that p + q = 1.0 If q, then p must = How many of these 50 offspring are homozygous dominant, heterozygous, or homozygous recessive? p² + 2pq+q² = 1.0 (100%) Formula: Translation: (pxp) + (2xpxq) + (qxq) = 1.0 (100%) Substitute numbers: ( x) + (2x x ) + ( x ) = 1.0 (100%) C Work out numbers: 4 p² = 2pq= q² = r + % % x 50 people in the population = % x 50 people in the population = % x 50 people in the population = Compare the allele distribution in Generation 1 with the allele distribution in Generation 2 (above). Has microevolution occurred? How do you know? 5 (p²) (2pq) (9²) + 6 011 y = 1.0 (100%) & 7 O homozygous dominant people (AA) heterozygous people (Aa) homozygous recessive people (aa) u * 8 O ( 9 ✓ ) 0 4 11 P

3 Allele distributions in Generation 1: 36 homozygous dominant individuals 13 heterozygous individuals 1 homozygous recessive individual There are 50 individuals in this particular population. We want to see if allele distributions change from generation to generation. We will use the Hardy Weinberg equations to find out. Due to migration and random mating of the parent generation, the percentage of homozygous recessive genotypes in Generation 2 offspring increases, changing "a" to 40%, so a = .40 If "a" = .40, and "a" = q, then q = Remember that p + q = 1.0 If q, then p must = How many of these 50 offspring are homozygous dominant, heterozygous, or homozygous recessive? p² + 2pq+q² = 1.0 (100%) Formula: Translation: (pxp) + (2xpxq) + (qxq) = 1.0 (100%) Substitute numbers: ( x) + (2x x ) + ( x ) = 1.0 (100%) C Work out numbers: 4 p² = 2pq= q² = r + % % x 50 people in the population = % x 50 people in the population = % x 50 people in the population = Compare the allele distribution in Generation 1 with the allele distribution in Generation 2 (above). Has microevolution occurred? How do you know? 5 (p²) (2pq) (9²) + 6 011 y = 1.0 (100%) & 7 O homozygous dominant people (AA) heterozygous people (Aa) homozygous recessive people (aa) u * 8 O ( 9 ✓ ) 0 4 11 P

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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# 3 e A = all of the dominant alleles for a particular trait in a specific population; a = all of the recessive alleles for a particular trait in a specific population In the following equations "A" is represented by "p"; "a" is represented by "q" Hardy Weinberg equations: Allele distributions in Generation 1: 36 homozygous dominant individuals 13 heterozygous individuals 1 homozygous recessive individual There are 50 individuals in this particular population. We want to see if allele distributions change from generation to generation. We will use the Hardy Weinberg equations to find out. p+q=1.0 (100% of the alleles for this trait in the population) Explanation of terminology: px p=p² 2 xpxq=2pq qxq=q² p² + 2pq+q² = 1.0 (Don't panic! You can do this!) Due to migration and random mating of the parent generation, the percentage of homozygous recessive genotypes in Generation 2 offspring increases, changing "a" to 40%, so a = .40 If "a" = .40, and "a"=q, then q = Remember that p+q=1.0 If q, then p must = How many of these 50 offspring are homozygous dominant, heterozygous, or homozygous recessive? p²+2pq+q² = 1.0 (100%) Formula: Translation: (pxp) + (2xpxq) + (qxq) = 1.0 (100%) Substitute numbers: ( X ) + (2x x ) + ( x ) = 1.0 (100%) Work out numbers: $ 4 r % 5 (p²) (2pq) Oll 6 y (9²) 081 & 7 O 1.0 (100%) * 00 8 O ( 9 al (44) ✓ O ) 0 ✔ P
Transcribed Image Text:# 3 e A = all of the dominant alleles for a particular trait in a specific population; a = all of the recessive alleles for a particular trait in a specific population In the following equations "A" is represented by "p"; "a" is represented by "q" Hardy Weinberg equations: Allele distributions in Generation 1: 36 homozygous dominant individuals 13 heterozygous individuals 1 homozygous recessive individual There are 50 individuals in this particular population. We want to see if allele distributions change from generation to generation. We will use the Hardy Weinberg equations to find out. p+q=1.0 (100% of the alleles for this trait in the population) Explanation of terminology: px p=p² 2 xpxq=2pq qxq=q² p² + 2pq+q² = 1.0 (Don't panic! You can do this!) Due to migration and random mating of the parent generation, the percentage of homozygous recessive genotypes in Generation 2 offspring increases, changing "a" to 40%, so a = .40 If "a" = .40, and "a"=q, then q = Remember that p+q=1.0 If q, then p must = How many of these 50 offspring are homozygous dominant, heterozygous, or homozygous recessive? p²+2pq+q² = 1.0 (100%) Formula: Translation: (pxp) + (2xpxq) + (qxq) = 1.0 (100%) Substitute numbers: ( X ) + (2x x ) + ( x ) = 1.0 (100%) Work out numbers: $ 4 r % 5 (p²) (2pq) Oll 6 y (9²) 081 & 7 O 1.0 (100%) * 00 8 O ( 9 al (44) ✓ O ) 0 ✔ P
3 Allele distributions in Generation 1: 36 homozygous dominant individuals 13 heterozygous individuals 1 homozygous recessive individual There are 50 individuals in this particular population. We want to see if allele distributions change from generation to generation. We will use the Hardy Weinberg equations to find out. Due to migration and random mating of the parent generation, the percentage of homozygous recessive genotypes in Generation 2 offspring increases, changing "a" to 40%, so a = .40 If "a" = .40, and "a" q, then q = Remember that p + q = 1.0 If q, then p must = How many of these 50 offspring are homozygous dominant, heterozygous, or homozygous recessive? p² + 2pq+q² = 1.0 (100%) Formula: Translation: (pxp) + (2xpxq) + (qxq) = 1.0 (100%) Substitute numbers: ( x) + (2x x ) + ( x ) = 1.0 (100%) C Work out numbers: 4 p² = 2pq= q² = r + % % x 50 people in the population = % x 50 people in the population = % x 50 people in the population = Compare the allele distribution in Generation 1 with the allele distribution in Generation 2 (above). Has microevolution occurred? How do you know? 5 (p²) (2pq) (9²) + 6 011 y = 1.0 (100%) & 7 O homozygous dominant people (AA) heterozygous people (Aa) homozygous recessive people (aa) u * 8 O ( 9 ✓ O ) 0 4 P
Transcribed Image Text:3 Allele distributions in Generation 1: 36 homozygous dominant individuals 13 heterozygous individuals 1 homozygous recessive individual There are 50 individuals in this particular population. We want to see if allele distributions change from generation to generation. We will use the Hardy Weinberg equations to find out. Due to migration and random mating of the parent generation, the percentage of homozygous recessive genotypes in Generation 2 offspring increases, changing "a" to 40%, so a = .40 If "a" = .40, and "a" q, then q = Remember that p + q = 1.0 If q, then p must = How many of these 50 offspring are homozygous dominant, heterozygous, or homozygous recessive? p² + 2pq+q² = 1.0 (100%) Formula: Translation: (pxp) + (2xpxq) + (qxq) = 1.0 (100%) Substitute numbers: ( x) + (2x x ) + ( x ) = 1.0 (100%) C Work out numbers: 4 p² = 2pq= q² = r + % % x 50 people in the population = % x 50 people in the population = % x 50 people in the population = Compare the allele distribution in Generation 1 with the allele distribution in Generation 2 (above). Has microevolution occurred? How do you know? 5 (p²) (2pq) (9²) + 6 011 y = 1.0 (100%) & 7 O homozygous dominant people (AA) heterozygous people (Aa) homozygous recessive people (aa) u * 8 O ( 9 ✓ O ) 0 4 P
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