3 1. A uniform solid sphere rolls without slipping down a 28° inclined plane. What is the acceleration of the sphere's center of mass? The moment of inertia of a uniform solid sphere about an axis that passes through its center = mr². The moment of inertia of a uniform solid sphere about an axis that is tangent to its surface = 7/5mr², m/s² E D C $ MAI 2 22 R 5 V 10 T G tv MacBook Air 6: B H U N * 00 8 ( 9 M K ) O P 11 A y m 04 M M
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- P A 1 n 1. A uniform solid sphere rolls without slipping down a 27° inclined plane. What is the acceleration of the sphere's center of mass? The moment of inertia of a uniform solid sphere about an axis that passes through its center = mr²2, The moment of inertia of a uniform solid sphere about an axis that is tangent to its surface = 7/5mr², m/s2 N 2 W S #3 X H command E с D $ 4 C R FL % 5 V 1332 Search or type URL T G ^ MacBook Pro 6 B Y H & 7 N U J * 00 1332 8 M - + K ( 9 O < ) 0 L P ^ : ; command option { [ ? 1 + 11For a solid disk, I= ½ mr?. If a solid disk of mass=5.0 kg has a radius of .25 m has force of 12 N exerted at the rim: (Remember significant digits.) a.) What is the angular moment of inertia (I)? kgm2 b.) What is the magnitude of the torque exerted? Nm c.) What is the magnitude of the angular acceleration of the disk? rad/s?A disk of radius R and thickness t has a mass density that increases from the center outward, given by p = po (r/R), where r is the distance from the axis of the disk. What is the moment of inertia about the disk axis in terms of M and R? O MR 2MR O sMP 3MR 5 O 2MR 3 5MR 3
- A uniform sphere is placed inside hemispherical bowl of radius R = 75.0 cm. It is released from rest at an angle 0 = 40.0°. What is the speed of the sphere at the bottom of the bowl if it rolls without slipping? Ishpere = 2/5 mr². Assume r<A figure skater rotating at 50.00 rad/s with arms extended has a moment of inertia of 4.5 kg. m^2. If the arms are pulled in so the moment of inertia decreases to 1.80 kg. m^2, what is the final angular speed? O 17.6 rad/s 12.25 rad/s 0.125 rad/ s 0.81 rad/s 125 rad /sT m A 25.0 kg mass is hung from a rope that is passed over a pulley and held by a man standing on a ramp. The pulley can be treated as a solid disk with a mass of 10.0 kg that has a radius of 0.400 m. The man pulls the rope so that the pulley rotates from rest through an angular displacement of 15.0 rad in 2.00s. A. What is the angular acceleration of the disk? B. What is the tension of the rope as it pulls up on the box? C. What is the force applied by the man on the rope as he pulls the box upward?A spherical shell with a mass of 1.43 kg and a radius of 0.39 m is rolling across the level ground with an initial angular velocity of 35.9 rad/s. It is slowing at an angular rate of 2.6 rad/s². What is its rotational kinetic energy after 4.7 s? The moment of inertia of a spherical shell is I = 글MR2A circular disk with a radius of 0.45 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. The mass of the disc is 0.59 kg. The moment of inertia of a disc is I MR? F1 = 2.3 N applied at the outer edge of the disc. %D F2 = 4.3 N applied at a distance of 0.21 from the center of the disc. What is the angular acceleration of the disc?A 1702 kg solid sphere with a radius of 2.6 m rolls without slipping down an incline of 0 = 41°. If the sphere makes 6 full revolutions in 8.4 seconds. 1. The rotational inertia of the sphere is kg.m2 2. The frictional force between the incline and the sphere is 3. The angular velocity at point C on the sphere is rad/s 4. The speed of the center of mass of the Sphere is m/s 5. The distance S after 6 full revolutions is mSuppose a disk with constant angular velocity has rotational kinetic energy 1280 J. If the moment of inertia of the disk is 35 kg-m?, then what is its angular velocity? 8.552 rad/s 9.066 rad/s С. 7.303 rad/s 10.07 rad/s 10.40 rad/s А. D. В. E. 10.14 rad/s F.2 W S X 24919 3 E D C 3. A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.45 x 10¹ rad/s to an angular speed of 3.75 x 104 rad/s. In the process, the bit turns through 2.26 x 10¹ rad. Assuming a constant angular acceleration, how long would it take the bit to reach its maximum speed of 7.10 x 10 rad/s, starting from rest? $ R F V % 5 19 T G tv B MacBook Air 6: Y H & 7 N 44 U ★ 8 J P M ( 9 K MOSISO V H 2 command 4 option y m 04 MA 85.0-kg skater begins a spin with an angular speed of 8.00 rad/s. By changing the position of her arms, the skater decreases her moment of inertia to one-fourth its initial value. What is the skater's final angular speed? my final answer is 16 rad/s? I'm not sure if it's correct because on test it was marked as incorrect. Can you please explain why it's incorrect?SEE MORE QUESTIONS