(2t+1) Find the derivative of S (t) = e6t eot (3(2t + 1)2 (2))- (2t + 1)³ (e* (6)) (e6t)2 s' (t) = (2t + 1) (et (6)) – eôt (3(2t + 1)² (2)) (e6t)2 s'(t) : e6t (3(2t + 1)(2)) – (2t + 1)³ (e®' (6)) (ebt)2 s'(t) = ebt (3(2t + 1)2 (2)) – (2t + 1)³ (et) (e6t)2 s'(t) =

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