(2t+1) Find the derivative of S (t) = e6t eot (3(2t + 1)2 (2))- (2t + 1)³ (e* (6)) (e6t)2 s' (t) = (2t + 1) (et (6)) – eôt (3(2t + 1)² (2)) (e6t)2 s'(t) : e6t (3(2t + 1)(2)) – (2t + 1)³ (e®' (6)) (ebt)2 s'(t) = ebt (3(2t + 1)2 (2)) – (2t + 1)³ (et) (e6t)2 s'(t) =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(2t+1)
Find the derivative of S (t) =
e6t
et (3(2t + 1)2 (2))- (2t + 1) (et (6))
(e6t)2
s' (t) =
(2t + 1) (et (6)) – eôt (3(2t + 1)² (2))
(e6t)2
s'(t)
e (3(2t + 1)(2))- (2t + 1)³ (e* (6))
s'(t) =
(e6t)2
ebt (3(2t + 1) (2)) – (2t + 1)* (et)
(e6t)2
s' (t) =
Transcribed Image Text:(2t+1) Find the derivative of S (t) = e6t et (3(2t + 1)2 (2))- (2t + 1) (et (6)) (e6t)2 s' (t) = (2t + 1) (et (6)) – eôt (3(2t + 1)² (2)) (e6t)2 s'(t) e (3(2t + 1)(2))- (2t + 1)³ (e* (6)) s'(t) = (e6t)2 ebt (3(2t + 1) (2)) – (2t + 1)* (et) (e6t)2 s' (t) =
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