_y'(x) = y = (x³ + 2)²(x²+4)*

Q: Find y'. y = log:(x* - 4x² + 2)

A:

Q: f(x) = (6x – 4)* - (4x² + 5)³. f'(x) =

A: Using product rule and chain rule of derivative,

Q: f(x)=xcosh^−1(x/2)−√x2−4 then f'(5)

A:

Q: Differentiate. V(x) = (3x³ + 3)(x* – 2x) V '(x) =

A:

Q: h(x)=3(5x³ -2x² +6)'. Find h'(x).

A: Given, h(x) = 3(5x3 -2x2 +6 )7

Q: Let (v 6x - 8 f(x) = ln %3D 5x + 4 f'(x) =

A:

Q: if f(x)=(4x+8)^-4 find f'(x) and f'(3).

A: Given:- f(x) = (4x+8)-4 To find:- f'(x) and f'(3)

Q: g(t)=4t^3+3t^2, find g’(3)=

A:

Q: ∫((X^2)/((1+X^2)^2)) dx

A:

Q: Differentiate. G(x) = (4x2 +5) (4x+ Vx) G'(x) = %D

A:

Q: V(x) = (5x³ + 3)(x* – 2x) V'(x)

A:

Q: Find f'(x) and simplify. f(x) = x5 Inx ○ A. (x5) (3) - (Inx) (5x) ○ B. (1) (5x4) ○ c. (x5) (5x4) +…

A: If you have any problem let me know here in comment box for this thankyou.

Q: If f(x) = (2x-1)^6 (x+3)^5, then f'(0)=

A:

Q: ∫[((x-1)^3)/(x^2)]dx

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Q: y= t(ln4t)^2      find y Prime

A:

Q: 3X (x³+

A:

Q: If 87 + 2 f(x) + 3x² (ƒ(x))³ = 0 and ƒ(1) = −3, find ƒ'(1).

A: 87+2f(x)+3x2(f(x))3=0,f(1)=−3

Q: find f'(x) or f(x)=(x^2+2)^3

A:

Q: f(x)=−6indexroot3√x−1/x^8 find f'(x)=

A: Given,           fx=-6x3-1x8

Q: Suppose f(x)=ln((ex2)/(x-6)7). Find f'(x)

A: We have to find f'(x).

Q: 1 2 30x(x − 1) ¹ dx is

A:

Q: y=(x^2+1)^4 y`(1)=?

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Q: Find d/dx((x)(d/dx(x-x^2))

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Q: Find h(x) if h'(x)= h(x): 5x (6-x²)² X and h(1) = -6.

A: NOTE: Refresh your page if you can't see any equations. . here we have take integration on both…