2H₂S(g) = 2H₂(g) + S₂(g) A 6.82 g sample of H2S gas is heated in a 0.500 L rigid container. At equilibrium, 0.06605 mol H2₂ gas is present in the sealed container. Calculate the equilibrium concentration of H2S(g) under these conditions. [H₂S] = [?] mol/L

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter13: Chemical Equilibrium
Section: Chapter Questions
Problem 129MP: A gaseous material XY(g) dissociates to some extent to produce X(g) and Y(g): XY(g)X(g)+Y(g) A...
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**Equilibrium Calculation of Gas Concentrations**

**Equation:**
\[ 2H_2S(g) \leftrightarrow 2H_2(g) + S_2(g) \]

**Description:**
A 6.82 g sample of \( H_2S \) gas is heated in a 0.500 L rigid container. At equilibrium, 0.06605 mol \( H_2 \) gas is present in the sealed container.

**Task:**
Calculate the equilibrium concentration of \( H_2S \) gas under these conditions.

**Equation to Solve:**
\[ [H_2S] = \boxed{?} \] mol/L

**Input & Submission:**
\[ H_2S \, \text{mol/L} \] 
(Input Box) [Enter] 

**Explanation of Graph or Diagram:**
There is no graph or diagram present in the image. The task is straightforward and requires the use of stoichiometry and equilibrium principles to solve for the equilibrium concentration of \( H_2S \).
Transcribed Image Text:**Equilibrium Calculation of Gas Concentrations** **Equation:** \[ 2H_2S(g) \leftrightarrow 2H_2(g) + S_2(g) \] **Description:** A 6.82 g sample of \( H_2S \) gas is heated in a 0.500 L rigid container. At equilibrium, 0.06605 mol \( H_2 \) gas is present in the sealed container. **Task:** Calculate the equilibrium concentration of \( H_2S \) gas under these conditions. **Equation to Solve:** \[ [H_2S] = \boxed{?} \] mol/L **Input & Submission:** \[ H_2S \, \text{mol/L} \] (Input Box) [Enter] **Explanation of Graph or Diagram:** There is no graph or diagram present in the image. The task is straightforward and requires the use of stoichiometry and equilibrium principles to solve for the equilibrium concentration of \( H_2S \).
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