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2HI (g) H2(g) + I2(g) At equilibrium the partial pressures are as follows : PHI = 0.708 atm,, PH2 and PI2 are 0.0960 atm. What is the value of Kp ? 6.80 × 10-2 1.30 x 10-2 1.84 x 10-2 4.70 × 10-2

2HI (g) H2(g) + I2(g) At equilibrium the partial pressures are as follows : PHI = 0.708 atm,, PH2 and PI2 are 0.0960 atm. What is the value of Kp ? 6.80 × 10-2 1.30 x 10-2 1.84 x 10-2 4.70 × 10-2

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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2HI (g) H2(g) + I2(g) At equilibrium the partial pressures are as follows : PHI = 0.708 atm, PH2 and PI, are 0.0960 atm. What is the value of Kp ? 6.80 × 10-2 1.30 x 10-2 1.84 x 10-2 4.70 × 10-2
Transcribed Image Text:2HI (g) H2(g) + I2(g) At equilibrium the partial pressures are as follows : PHI = 0.708 atm, PH2 and PI, are 0.0960 atm. What is the value of Kp ? 6.80 × 10-2 1.30 x 10-2 1.84 x 10-2 4.70 × 10-2
Expert Solution
Step 1

• The given reaction is, 

          2HI(g) ⇌ H2(g) + I2(g) 

 

• The values provided in the question are:- 

i) Equilibrium partial pressure of HI, PHI = 0.708 atm 

ii) Equilibrium partial pressure of H2, PH2 = 0.0960 atm 

iii) Equilibrium partial pressure of I2, PI2 = 0.0960 atm 

 

• We need to calculate the equilibrium constant, Kp in terms of pressure for the reaction. 

 

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