2d d P + V. A particle of charge +q and mass m is ejected from the point P with the initial velocity v = 20î + 10f(=), traveling in a parabolic orbit with a maximum height d = 2cm in the uniform electric field and hitting the point Q at a distance of L = 10cm. Since the distance between the plates is 2d and the potential difference is 1000V, find the ratio of the particle's charge to its mass (q/m). (Ignore the gravitational force).

2d d P + V. A particle of charge +q and mass m is ejected from the point P with the initial velocity v = 20î + 10f(=), traveling in a parabolic orbit with a maximum height d = 2cm in the uniform electric field and hitting the point Q at a distance of L = 10cm. Since the distance between the plates is 2d and the potential difference is 1000V, find the ratio of the particle's charge to its mass (q/m). (Ignore the gravitational force).

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A particle of charge q is fixed at point P, and a second particle of mass m and the same charge q is initially held a distance r1 from P. The second particle is then released. Determine its speed when it is a distance r2 from P. Let q = 2.8 µC, m = 30 mg, r1 = 1.3 mm, and r2 = 2.6 mm.
A positive charge of 4.20 μC is fixed in place. From a distance of 4.20 cm a particle of mass 6.20 g and charge +3.00 μC is fired with an initial speed of 62.0 m/s directly toward the fixed charge. How close to the fixed charge does the particle get before it comes to rest and starts traveling away? (in cm)
Two parallel plates are separated ?=0.00375 mx=0.00375 m and have a potential difference of ?=1610 V.V=1610 V. A small ball with mass ?=9.10×10−12 kgm=9.10×10−12 kg is placed between the two plates and remains motionless and floating between the plates. From the overall charge on the ball, determine the number of electrons ?ene the ball has gained or lost. The acceleration due to gravity is ?=9.81 m/s2,g=9.81 m/s2, and the elementary unit of charge is ?=1.60×10−19 C.
A light, unstressed spring has length d. Two identical particles, each with charge q, are connected to the opposite ends of the spring. The particles are held stationary a distance d apart and then released at the same moment. The system then oscillates on a frictionless, horizontal table. The spring has a bit of internal kinetic friction, so the oscillation is damped. The particles eventually stop vibrating when the distance between them is 3d. Assume the system of the spring and two charged particles is isolated. Find the increase in internal energy that appears in the spring during the oscillations.
Two horizontal parallel plates are separated by a distance of 165mm creating an electric field of 32 µN/C directed north. An electron is place halfway between the two plates with and fired with initial velocity 67m/s from the horizontal. Calculate the time it takes for the electron to land at the positive plate and its speed before hitting the plate,
Problem 4 (practice): A mad scientist considers creating a roller coaster which would use a uniform electric field to accelerate the roller coaster cars at the start of the ride. One coaster car has a mass of 250 kg, and the scientist manages to place 0.003 C of charge on it. How strong of an electric field would they need in order to get the coaster to go from rest to a speed of 17 m/s within a distance of 20 meters?
Particle 1 has mass 3.00 g and charge +8.00 μC. Particle 2 has mass 6.00 g and the same charge. They are held at rest a distance d apart and then released, after which they fly apart. When the distance between them is 0.300 m, particle 2 has a speed of 64.0 m/s. What was the initial separation d? 0.781 cm 1.506 cm 1.485 cm 10.0 cm 0.675 cm
In the figure an electron is shot at an initial speed of v0 = 5.63 × 106 m/s, at angle θ0 = 44.9 ˚ from an x axis. It moves through a uniform electric field E→ = (3.42 N/C)j→. A screen for detecting electrons is positioned parallel to the y axis, at distance x = 1.62 m. What is the y component of the electron's velocity (sign included) when the electron hits the screen?
A particle possessing ?=9.25 μCq=9.25 μC of charge and a mass of ?=4.55 gm=4.55 g is fired at a speed of ?=357 cm/sv=357 cm/s between two horizontal charged plates of length ?=44.7 cm. Assume that the electric field between the plates is uniform and has a constant value of ?=965 N/C,E=965 N/C, directed upwards. Calculate the distance ?y by which the charge falls below a straight‑line path when it reaches the end of the plates. Assume a gravitational acceleration of ?=9.81m/s2.
Two horizontal parallel plates are separated by a distance of 174 mm creating an electric field of 23 μN/C directed north. An electron is place halfway between the two plates with and fired with initial velocity 58 m/s from the horizontal. Calculate the time it takes for the electron to land at the positive plate and its speed before hitting the plate. Provide a Free-body diagram and answer in GRESA format.
A positively charged particle of mass 50 grams and charge 10 µC is released from rest at the origin in the uniform electric field of 100 N/C directed along the +X-axis. Determine its speed at x = 10 cm position.
In this example, we will analyze the motion of an electron that is released in an electric field. The terminals of a 100 VV battery are connected to two large, parallel, horizontal plates 1.0 cmcm apart. The resulting charges on the plates produce an electric field in the region between the plates that is very nearly uniform and has magnitude E� = 3.0×104 N/C. Suppose the lower plate has positive charge, so that the electric field is vertically upward, as shown in (Figure 1). (The thin pink arrows represent the electric field.) If an electron is released from rest at the upper plate, what is its speed just before it reaches the lower plate? How much time is required for it to reach the lower plate? The mass of an electron is me=9.11×10−31kg. Please refer to the photos